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elena-14-01-66 [18.8K]
2 years ago
12

A construction worker needs to put in a rectangular window in the side of a building. He knows from measuring that the top and b

ottom of the window has a width of 5ft and the sides have a length of 12ft. He also measured a diagonal of 13 ft. What is the length of the other diagonal?
Mathematics
1 answer:
maksim [4K]2 years ago
7 0

Answer:

13

Step-by-step explanation:

The diagonals of a rectangle are congruent.

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in triangleABC the side lengths are b=13, ac=21 and bc=x. write a compound inequality the represents the range of possible value
tankabanditka [31]

Answer:

8 < x < 34

Step-by-step explanation:

ab = 13, ac = 21, bc = x

The longest side of a triangle must be less than the sum of the other two sides.

If 21 is the longest side:

21 < 13 + x

8 < x

If x is the longest side:

x < 13 + 21

x < 34

Therefore, 8 < x < 34.

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Two galaxies are shown. Galaxy U: Dust, gas, and stars in the shape of a pinwheel, relatively small in size. Galaxy NGC 1427A: D
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Answer:

NGC 1427A has no general shape, so it is an irregular galaxy. U has a bulge in the center and arms, so it is a spiral galaxy. They are similar in that both contain plenty of dust and gas. Both also have active star-forming sites.

Step-by-step explanation: Got it right on the test

8 0
2 years ago
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133 1/3 % of what number is 74?
vfiekz [6]
1.333 ×x = 74

x =
\frac{74}{1.333} = 55.50
4 0
2 years ago
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Using the defects method, which of these relationships represents the Law of Cosines if the measure of the included angle betwee
horrorfan [7]
Asked and answered elsewhere.
brainly.com/question/1410592

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4 0
2 years ago
Given the formula b=rs/t solve for s
Gekata [30.6K]

Answer:

s = \frac{bt}{r}

Step-by-step explanation:

To solve for s, you need to follow these steps.

First multiply by t both sides of the equation.

b = \frac{rs}{t}

bt = \frac{rst}{t}

We get bt = rs

Now we divide by r, both sides of the equation.

\frac{bt}{r} = \frac{rs}{r}

Finallly we obtain:

\frac{bt}{r} = s or

s = \frac{bt}{r}

7 0
2 years ago
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