m • (g4c - 3)
(1):g4 was replaced by g^4.
Pulling out like terms:
2.1:Pull out like factors:
g4cm - 3m = m • (g4c - 3)
Trying to factor as a Difference of Squares :
2.2:Factoring: g4c - 3
Given
One month julia collected 8.4 gallons of rainwater.
she used 5.2 gallons of rainwater to water her garden
6.5 gallons of rainwater to water flowers
Find out how much was the supply of rainwater increased or decreased by the end of the month.
To proof
As given in the question
One month julia collected 8.4 gallons of rainwater
she used 5.2 gallons of rainwater to water her garden and 6.5 gallons of rainwater to water flowers
Total water she used in the month = 5.2 gallons + 6.5gallons
= 11.7 gallons
Let the supply of rainwater increased or decreased by the end of the month
be x .
Than the equation become in the form
x + 8.4 = 11.7
x = 3.3 gallons
Therefore the supply of rainwater increased or decreased by the end of the month is 3.3 gallons.
Hence proved
Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
We will take the volume of each box separately to find the difference between them.
We have then that the volume of the boxes is:
V = (L) * (W) * (h)
Where,
L: long
W: width
h: height
The smaller box:
V1 = (12) * (2) * (7 3/4)
V1 = 186 in ^ 3
the lager box:
V2 = (12) * (2) * ((7 3/4) * (100/80))
V2 = 232.5 in ^ 3
The difference is:
V2-V1 = 232.5 in ^ 3 - 186 in ^ 3 = 46.5 in ^ 3
Answer:
The difference in the volumes of the two boxes is:
46.5 in ^ 3
