Find the common difference of the arithmetic sequence. 6,9.4,12.8,16.2
1 answer:
A sequence is said to be arithmetic if every couple of adjacent elements differ by the same number. If this is the case, that constant number is called the common difference.
This sequence is arithmetic, because the difference between every element and the previous one is
So, the common differnece is 3.4, because every couple of adjacent terms differ by 3.4
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We know the following relationship:
The domain of a function are the inputs of the function, that is, a function
is a relation that assigns to each element 
in the set A exactly one element in the set B. The set A is the domain (or set of inputs) of the function and the set B contains the range (or set of outputs).Then applying this concept to our function 
we can write its domain as follows:
1. D<span>omain of validity for:
</span>
When:
?
when:
where k is an integer either positive or negative. That is:
To match this with the choices above, the answer is:
<span>"All real numbers except multiples of
"
</span>
2. which identity is not used in the proof of the identity
:
This identity can proved as follows:
The identity that is not used is as established in the statement above:
<span>"1 +cos squared theta over sin squared theta= csc2theta"
Written in mathematical language as follows:
</span>
<span>
</span>
The domain of a function are the inputs of the function, that is, a function
1. D<span>omain of validity for
</span>
When:
when:
where k is an integer either positive or negative. That is:
To match this with the choices above, the answer is:
<span>"All real numbers except multiples of
</span>
2. which identity is not used in the proof of the identity
This identity can proved as follows:
The identity that is not used is as established in the statement above:
<span>"1 +cos squared theta over sin squared theta= csc2theta"
Written in mathematical language as follows:
</span>
</span>
Answer:
Step-by-step explanation:
Given that X is a normal random variable with parameters µ = 10 and σ 2 = 36,
X is N(10, 6)
Or z =
is N(0,1)
a) P(X > 5),
=
(b) P(4 < X < 16),
=
(c) P(X < 8),
=
(d) P(X < 20),
=
(e) P(X > 16).
=P(Z>-0.6667)
= 0.2524