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1 year ago

What value of x is in the solution set of 2(3x – 1) ≥ 4x – 6?

2 answers:

6 0

2(3x-1) ≥ 4x-6
Distribute the 2 on the left side: 6x-2 ≥ 4x-6

Move terms to solve for x:

2x ≥ -4

x ≥ -2

Therefore, any value from -2 to ∞ are valid solutions.

devlian [24]1 year ago

5 0

Answer:

x ≥ – 2. { -2, -1, 0, 1,2,.....

Step-by-step explanation:

Given : 2(3x – 1) ≥ 4x – 6.

To find : What value of x is in the solution set .

Solution : We have given that

2(3x – 1) ≥ 4x – 6.

Distribute 2 over (3x -1)

6x -2 ≥ 4x – 6.

On subtracting both sides by 4x

6x -2 - 4x ≥ – 6.

On adding both sides by 2

2x ≥ – 6+ 2.

2x ≥ – 4.

On dividing both sides by 2

x ≥ – 2.

Therefore, x ≥ – 2. { -2, -1, 0, 1,2,.....

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1 year ago

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Step-by-step explanation:

This survey will not be reliable as it is chosen for convenience; the first 120 students to arrive in school on a particular morning and this collection of individuals may not be a representative of the population. The study may become biased because it does not take into account the latecomers among the students which might have been changed the study from systematically favoring certain outcomes.

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2 years ago

An expression is given: 2 open parentheses square root of k minus 1 close parenthesis plus square root of 8. If on adding negati

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Answer:

Possible value of k is √2

Step-by-step explanation:

The information given are;

The expression, 2·(√k - 1) + √8 to which may be added -6·√2 to obtain a rational number, we therefore have;

2·(√k - 1) + √8 - 6·√2 = R

Therefore, simplifying gives;

2·√k - 2 + 2·√2 - 6·√2 = 2·√k - 2 - 4·√2 = R

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(√k - 2·√2) = R/2 = R

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2 years ago

Food allergies affect an estimated 7% of children under age 5 in the US. What is the probability that in a kindergarden class of

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Answer:

Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)

Step-by-step explanation:

Given: Probability of a children under age 5 has food allergies = 7%

= $\frac{7}{100}$

To find : Probability of atleast one of 12 student has food allergies

Probability of a chindren under age 5 does not have food allergies = $1-\frac{7}{100}$

⇒ prob = $\frac{93}{100}$

now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.

But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)

Probability of 0 student having allergy out of 12 student = $(\frac{93}{100})^{12}$