Jen is on the platform of her boat. She sights the top of a lighthouse at an angle of 30° as shown below. She knows that the hei
1 answer:
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After reducing the fraction it becomes equal to 5/12. Let the common element which was cancelled out be x. So we can say the original fraction was 
.
The denominator of the fraction is 147 greater than the numerator. We can write it as:
12x = 147 + 5x
12x - 5x = 147
7x = 147
x = 21
So, the numerator of the fraction was 5 x 21 = 105
Denominator of the fraction was 12 x 21 = 252
So our original fraction was
The denominator of the fraction is 147 greater than the numerator. We can write it as:
12x = 147 + 5x
12x - 5x = 147
7x = 147
x = 21
So, the numerator of the fraction was 5 x 21 = 105
Denominator of the fraction was 12 x 21 = 252
So our original fraction was
Answer:
the base of the ladder is 27.89 ft away from the building
Step-by-step explanation:
Notice that this situation can be represented with a right angle triangle. The right angle being that made between the ground and the building, the ladder (32 ft long) being the hypotenuse of the triangle, the acute angle of being adjacent to the unknown side we are asked about (x). So, we can use the cosine function to solve this:
which rounded to the nearest hundredth gives;
x = 27.89 ft
Answer:
Largest possible length is <em>21 inches</em>.
Step-by-step explanation:
Given:
Total material available = 60 inches
Length to be 3 more than twice of width.
To find:
Largest possible length = ?
Solution:
As it is rectangular shaped frame.
Let length = inches and
Width = inches
As per given condition:
..... (1)
Total frame available = 60 inches.
i.e. it will be the perimeter of the rectangle.
Formula for perimeter of rectangle is given as:
Putting the given values and conditions as per equation (1):
Putting in equation (1):
So, the answer is:
Largest possible length is <em>21 inches</em>.
It looks like you're given
Then by the additivity of definite integrals this is the same as
(presumably this is what the hint suggests to use)
Then by the fundamental theorem of calculus, we have