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Gre4nikov [31]
1 year ago
12

Osama starts with a population of 1,000 amoebas that increases 30% in size every hour for a number of hours, h. The expression 1

,000(1+0.3)h finds the number of amoebas after h hours. Which statement about this expression is true?
A. It is the product of the initial population and the growth factor after h hours.


B. It is the sum of the initial population and the percent increase.


C. It is the initial population raised to the growth factor after h hours.


D. It is the sum of the initial population and the growth factor after h hours.
Mathematics
2 answers:
Blizzard [7]1 year ago
3 0

Answer: The correct option is A, itis the product of the initial population and the growth factor after h hours.

Explanation:

From the given information,

Initial population = 1000

Increasing rate or growth rate = 30% every hour.

No of population increase in every hour is,

1000\times \frac{30}{100} =1000\times 0.3

Total population after h hours is,

1000(1+0.3)^h

It is in the form of,

P(t)=P_0(t)(1+r)^t

Where P_0(t) is the initial population, r is increasing rate, t is time and [tex(1+r)^t[/tex]  is the growth factor after time t.

In the above equation 1000 is the initial population and (1+0.3)^h is the growth factor after h hours. So the equation is product of of the initial population and the growth factor after h hours.

Therefore, the correct option is A, itis the product of the initial population and the growth factor after h hours.

Bogdan [553]1 year ago
3 0

Answer:

the answer should be A

Step-by-step explanation:

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Jacy has $1,000 to invest in either a fund that pays approximately 4.6% per year or in a savings account with an annual interest
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Answer:

S(x) = 0.046x + 0.018(1000-x)

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Given that:

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Let x is the amount Jacy invest in the fund so (1000-x) is the amount he invests in the  savings account​

So a polynomial  function S(x) to represent the interest Jacy will earn in 1 year is:

S(x) = 0.046x + 0.018(1000-x)

Hope it will find you well.

7 0
1 year ago
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Find the cube roots of 8(cos 216° + i sin 216°).
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z^3=8(\cos216^\circ+i\sin216^\circ)
z^3=2^3(\cos(6^3)^\circ+i\sin(6^3)^\circ)
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where k=0,1,2. So the third roots are

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1 year ago
Refer to the figure and find the volume V generated by rotating the given region about the specified line. R3 about AB.
mylen [45]

Answer: V = \frac{34}{45} \pi  


Explanation:

In the given system of coordinates OXY, the region R₃ is bounded by two functions:

y₁ = 2\sqrt[4]{x}  (green line)

y₂ = 2x  (blu line)

in the intervals:

0 ≤ x ≤ 1

0 ≤ y ≤ 2


We need to find the volume of this region rotated about the line AB, which is x = 1. In order to do so, we need to change system of coordinates, such as the rotation is about the y-axis, therefore we need to perform a translation:

\left \{ {{X=x+1} \atop {Y=y}} \right.

After the translation R₃ will be bounded by:

y₁ = 2\sqrt[4]{x+1}

y₂ = 2x + 2

in the intervals:

-1 ≤ x ≤ 0

0 ≤ y ≤ 2


At this point, we can use the washer method (see picture attached). The general formula is:

A = π(R² - r²)

where:

A = area

R = outer radius of a washer

r = inner radius of a washer


Since the radii are x-values which vary with the height, represented by the y-values, we need to write the inverse functions:

R: x_{1} = \frac{1}{16} y^{4} - 1 \\ r: x_{2} = \frac{1}{2} y - 1

[Note: I used the curves on the left side of the graph, but you could find the ones representing the right side of the graph and use those]


Now, we can find the function for the area of each washer:

A(y) = \pi [(\frac{1}{16}y^{4} - 1)^{2} - (\frac{1}{2}y - 1)^{2} ] \\ = \pi [\frac{1}{256}y^{8} - \frac{1}{8} y^{4} - \frac{1}{4} y^{2} + y ]


Therefore the volume of the region R₃ will be:

V = \int\limits^{y_{2}}_{y_{1}} {A(y)} \, dy

= \int\limits^2_0 {\pi [\frac{1}{256}y^{8} - \frac{1}{8}y^{4} - \frac{1}{4} y^{2} + y] } \, dy

= \pi [ \frac{1}{2304}y^{9} - \frac{1}{40}y^{5} - \frac{1}{12} y^{3} + \frac{1}{2} y^{2}]^{2}_{0}

= \frac{34}{45} \pi

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1 year ago
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