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Gre4nikov [31]
1 year ago
12

Osama starts with a population of 1,000 amoebas that increases 30% in size every hour for a number of hours, h. The expression 1

,000(1+0.3)h finds the number of amoebas after h hours. Which statement about this expression is true?
A. It is the product of the initial population and the growth factor after h hours.


B. It is the sum of the initial population and the percent increase.


C. It is the initial population raised to the growth factor after h hours.


D. It is the sum of the initial population and the growth factor after h hours.
Mathematics
2 answers:
Blizzard [7]1 year ago
3 0

Answer: The correct option is A, itis the product of the initial population and the growth factor after h hours.

Explanation:

From the given information,

Initial population = 1000

Increasing rate or growth rate = 30% every hour.

No of population increase in every hour is,

1000\times \frac{30}{100} =1000\times 0.3

Total population after h hours is,

1000(1+0.3)^h

It is in the form of,

P(t)=P_0(t)(1+r)^t

Where P_0(t) is the initial population, r is increasing rate, t is time and [tex(1+r)^t[/tex]  is the growth factor after time t.

In the above equation 1000 is the initial population and (1+0.3)^h is the growth factor after h hours. So the equation is product of of the initial population and the growth factor after h hours.

Therefore, the correct option is A, itis the product of the initial population and the growth factor after h hours.

Bogdan [553]1 year ago
3 0

Answer:

the answer should be A

Step-by-step explanation:

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A local pizzeria offers 15 toppings for their pizzas and you can choose any 3 of them for one fixed price. How many different ty
Shtirlitz [24]

Answer:

  455 or 680, depending

Step-by-step explanation:

If we assume the three choices are different, then there are ...

  15C3 = 15·14·13/(3·2·1) = 35·13 = 455

ways to make the pizza.

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If two or three of the topping choices can be the same, then there are an additional ...

  2(15C2) +15C1 = 2·105 +15 = 225

ways to make the pizza, for a total of ...

  455 + 225 = 680

different types of pizza.

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There is a factor of 2 attached to the number of choices of 2 toppings, because you can have double anchovies and tomato, or double tomato and anchovies, for example, when your choice of two toppings is anchovies and tomato.

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nCk = n!/(k!(n-k)!)

6 0
2 years ago
A piece of equipment moves 16.8 yards in 12 minutes how many feet does it move per second?
I am Lyosha [343]

convert yards to feet and minutes to seconds

1yard=3ft

16.8yards times 3ft/1yd=50.4ft


1minute=60 seconds

12minutes times 60seconds/1min=720seconds


feet per second=50.4ft/720sec=0.07ft/sec


answer is 0.07ft/sec

6 0
1 year ago
Expand the following expression by using the distributive method. 6(3b - 4c)
Kruka [31]
18b - 24c because you multiply the outside with everything inside

8 0
1 year ago
Given that a function, g, has a domain of -1 ≤ x ≤ 4 and a range of 0 ≤ g(x) ≤ 18 and that g(-1) = 2 and g(2) = 8, select the st
notka56 [123]

Options

  • (A)g(5) = 12
  • (B)g(1) = -2
  • (C)g(2) = 4
  • (D)g(3) = 18

Answer:

(D)g(3) = 18

Step-by-step explanation:

Given that the function, g, has a domain of -1 ≤ x ≤ 4 and a range of                       0 ≤ g(x) ≤ 18 and that g(-1) = 2 and g(2) = 8

Then the following properties must hold

  1. The value(s) of x must be between -1 and 4
  2. The values of g(x) must be between 0 and 18.
  3. g(-1)=2
  4. g(2)=9

We consider the options and state why they are true or otherwise.

<u>Option A: g(5)=12</u>

The value of x=5. This contradicts property 1 stated above. Therefore, it is not true.

<u>Option B: g(1) = -2 </u>

The value of g(x)=-2. This contradicts property 2 stated above. Therefore, it is not true.

<u>Option C: g(2) = 4 </u>

The value of g(2)=4. However by property 4 stated above, g(2)=9. Therefore, it is not true.

<u>Option D: g(3) = 18</u>

This statement can be true as its domain is in between -1 and 4 and its range is in between 0 and 18.

Therefore, Option D could be true.

3 0
2 years ago
Meeting at least one person with the flu in thirteen random encounters on campus when the infection rate is 2% (2 in 100 people
s344n2d4d5 [400]

Answer:

23.1% probability of meeting at least one person with the flu

Step-by-step explanation:

For each encounter, there are only two possible outcomes. Either the person has the flu, or the person does not. The probability of a person having the flu is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Infection rate of 2%

This means that p = 0.02

Thirteen random encounters

This means that n = 13

Probability of meeting at least one person with the flu

Either you meet none, or you meet at least one. The sum of the probabilities of these outcomes is 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). Then

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{13,0}.(0.02)^{0}.(0.98)^{13} = 0.7690

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.769 = 0.231

23.1% probability of meeting at least one person with the flu

6 0
1 year ago
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