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1 year ago

A tank holds 49 litres of oil. if 7 litres leaked what percentage of oul has leaked

Mathematics

1 answer:

REY [17]1 year ago

6 0

Answer:

14.3%

Step-by-step explanation:

7 liters of the 49 litre oil has been poured out. Since it is out of 49, divide 7 by 49 and multiply by 100 to find its percentage. bangg.

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A recent poll of 124 randomly selected residents of a town with a population of 310 showed that 93 of them are opposed to a new

tester [92]

The sample size is 124.
93 of them are opposed to new shopping center.

So,
n = 124
p = $\frac{93}{124}=0.75$

The point estimate of the population proportion = p = 0.75
q = 1 - p = 0.25

Margin of error (E) can be calculated by:

$E= Z_{c} \sqrt{ \frac{pq}{n} }$

Using the values, we get:

$E=1.645 \sqrt{ \frac{0.75*0.25}{124} }=0.06$

Therefore, the margin of error is approximately 0.06 or 6%.

6 0

2 years ago

Read 2 more answers

Nine new employees, two of whom are married to each other, are to be assigned nine desks that are lined up in a row. If the assi

meriva

Answer:

The probability is 0.8

Step-by-step explanation:

The key to answering this question is considering the fact that the two married employees be treated as a single unit.

Now what this means is that we would be having 8 desks to assign.

Mathematically, the number of ways to assign 8 desks to 8 employees is equal to 8!

Now, the number of ways the couple can interchange their desks is just 2 ways

Thus, the number of ways to assign desks such that the couple has adjacent desks is 2(8!)

The number of ways to assign desks among all six employees randomly is 9!

Thus, the probability that the couple will have adjacent desks would be ;

2(8!)/9! = 2/9

This means that the probability that the couple have non adjacent desks is 1-2/9 = 7/9 = 0.77778

Which is 0.8 to the nearest tenth of a percent

4 0

2 years ago

Which of the following is an accurate description of Simpson's paradox?

docker41 [41]

The answer to the question is a

6 0

2 years ago

Of the 500 sample households in the previous exercise, 7 had three or more large-screen TVs. (a) The percentage of households in

likoan [24]

Answer:

a) The percentage of households in the town with three or more largescreen TVs is estimated as :

The best estimation for the population proportion is :

$\hat p=\frac{7}{500}=0.014$

And that represent the 1.4%.

b) And the 95% confidence interval would be given (0.00370;0.0243).

And the % would be between 0.37% and 2.43%.

Step-by-step explanation:

Data given and notation

n=500 represent the random sample taken

X=7 represent the households with three or more large-screen TVs

$\hat p=\frac{7}{500}=0.014$ estimated proportion of households with three or more large-screen TVs

$\alpha=0.05$ represent the significance level (no given, but is assumed)

z would represent the statistic (variable of interest)

p= population proportion of households with three or more large-screen TVs

Part a

The percentage of households in the town with three or more largescreen TVs is estimated as :

The best estimation for the population proportion is :

$\hat p=\frac{7}{500}=0.014$

And that represent the 1.4%.

Part b

Yes is possible. We hav that $np>10$ and $n(1-p)>10$ so we have the assumption of normality to find the interval.

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.