Question

The pressure at sea level is 111 atmosphere and increases at a constant rate as depth increases. When Sydney dives to a depth of 232323 meters, the pressure around her is 3.33.33, point, 3 atmospheres. The pressure ppp in atmospheres is a function of xxx, the depth in meters.

Answer 1

Answer:

we have P(x) = mx + 1

Step-by-step explanation:

Allow me to revise your question for a better understanding:

The pressure at sea level is 1 atmosphere and increases at a constant rate as depth increases. When Sydney dives to a depth of 23 meters, the pressure around her is 3.3 point, 3 atmospheres. The pressure p in atmospheres is a function of x, the depth in meters.

My answer:

Given:

At O meter the the pressure is 1 (0, 1)

At 23 meters the the pressure is 3.3 (23, 3.3)

From that, we can form a linear equation with the standard form:

P(x) = mx + b (1)

The slope of (1) is:

$m=\frac{3.3-1}{23-0}=\frac{2.3}{23}=\frac{23}{230}=0.1$

<=> P(x) = 0.1x + b

Substitute the point (0, 1) into (1) we have:

1 = 0.1*0 + b

<=> b = 1

So we have the equation of this line will be: P(x) = mx + 1