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Fed [463]
2 years ago
7

Which function, g or h, is the inverse function for function ƒ? the function h because the graphs of ƒ and h are symmetrical abo

ut the y-axis the function g because the graphs of ƒ and g are symmetrical about the line y = x the function h because the graphs of ƒ and h are symmetrical about the line y = x the function g because the graphs of ƒ and g are symmetrical about the x-axis?
Mathematics
1 answer:
xz_007 [3.2K]2 years ago
4 0
A function and it's inverse function, when graphed, will be symmetrical across the line y=x. 
Without seeing your graphs, I can't tell you if it's g or h. Look for the function which mirrors 'f' across y=x, which is a diagonal line passing through the origin (0,0) of the graph. 
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Jeanne wants to start collecting coins and orders a coin collection starter kit. The kit comes with three coins chosen at random
lesya692 [45]
Conditional probability is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, "the conditional probability of A given B", or "the probability of A under the condition B", is usually written as P(A|B), or sometimes P_B(A).

The conditional probability of event A happening, given that event B has happened, written as P(A|B) is given by
P(A|B)= \frac{P(A \cap B)}{P(B)}

In the question, we were told that there are three randomly selected coins which can be a nickel, a dime or a quarter.

The probability of selecting one coin is \frac{1}{3}

Part A:
To find <span>the probability that all three coins are quarters if the first two envelopes Jeanne opens each contain a quarter, let the event that all three coins are quarters be A and the event that the first two envelopes Jeanne opens each contain a quarter be B.

P(A) means that the first envelope contains a quarter AND the second envelope contains a quarter AND the third envelope contains a quarter.

Thus P(A)= \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1}{27}

</span><span>P(B) means that the first envelope contains a quarter AND the second envelope contains a quarter

</span><span>Thus P(B)= \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}

Therefore, P(A|B)=\left( \frac{ \frac{1}{27} }{ \frac{1}{9} } \right)= \frac{1}{3}


Part B:
</span>To find the probability that all three coins are different if the first envelope Jeanne opens contains a dime<span>, let the event that all three coins are different be C and the event that the first envelope Jeanne opens contains a dime be D.
</span><span>
P(C)= \frac{3}{3} \times \frac{2}{3} \times \frac{1}{3} = \frac{6}{27} = \frac{2}{9}

</span><span>P(D)= \frac{1}{3}</span><span>

Therefore, P(C|D)=\left( \frac{ \frac{2}{9} }{ \frac{1}{3} } \right)= \frac{2}{3}</span>
3 0
2 years ago
The photo shows a small coin. The scale from the actual coin to the photo is
Aleks [24]

8mm to 2cm is the same as 8mm to 20mm

8 : 20 simplifies to 2 : 5

3.25cm ÷ 5 = 0.65cm

0.65 x 2 = 1.3cm

Your answer is 1.3cm

6 0
2 years ago
T(m)=0.04m+1.26?? I don't understand how to solve it...
Marat540 [252]
You gotta move that b to the side ya digg
3 0
2 years ago
Put these measurements in order from largest to smallest: 9000ml, 0.048 kl, 4.8L
Helen [10]

As the highest measurement unit given is KL, we will convert the other values to KL to arrange from largest to smallest or descending order.

Converting the given values we get:

9000 ml =  0.009 KL

4.8 L = 0.0048 KL

Third given is 0.048 KL

So, now arranging them from largest to smallest we get,

0.048 KL, 0.009 KL, 0.0048 KL

Hence the correct order is:

0.048 KL, 9000 ml, 4.8 L

5 0
2 years ago
Juan walks a circular path with a radius of 280 yards at the local park. How far does she walk? Use 3.14 for pi.
belka [17]
Answer: Juan walks 246,176 yards around the circular path.

To find the distance around the circular path, we are looking for the circumference. The formula for the circumference is: C = pi(r^2).

Simply plug in the radius and evaluate the expression.

C = 3.14(280^2)
C = 3.14(78400)
C = 246,176 yd
4 0
2 years ago
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