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2 years ago

The photo shows a small coin. The scale from the actual coin to the photo is

Mathematics

1 answer:

Aleks [24]2 years ago

6 0

8mm to 2cm is the same as 8mm to 20mm

8 : 20 simplifies to 2 : 5

3.25cm ÷ 5 = 0.65cm

0.65 x 2 = 1.3cm

Your answer is 1.3cm

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A dust particle weighs 7.42 × 10-10 kilograms. What is the weight of 5 × 106 dust particles represented in scientific notation?

vova2212 [387]

5 x 106 = 530 particles

530 x 7.42x10^-10 = 3.93x10^-7

7 0

2 years ago

Read 2 more answers

Two trains start from Fort Worth traveling at the same speed. The trip for Train W takes 20 hours, while the trip for Train Z ta

MrMuchimi

Answer:

The equation that best models this situation is :

b. $\frac{x}{20}=\frac{x+400}{25}$

Distance traveled by Train W = 1600 miles

Distance traveled by Train Z = 2,000 miles

Step-by-step explanation:

Given:

Time taken for Train W to complete a trip = 20 hours

Time taken for Train Z to complete a trip = 25 hours

The city Train Z is traveling to is 400 miles farther away than the city Train W is traveling to.

both trains have same speeds and start from same location.

To find the distance in total each train travels.

Solution:

<em>Let length of the trip of Train W be </em>= $x$ miles

Speed of Train W can be given as :

⇒ $\frac{Distance}{Time}$

⇒ $\frac{x}{20}\ miles/h$

<em>So, the length of the trip of Train Z will be</em> = $(x+400)$ miles

Speed of Train Z can be given as :

⇒ $\frac{Distance}{Time}$

⇒ $\frac{x+400}{25}\ miles/h$

Since the speeds are same, so the equation to find $x$ can be given as:

⇒ $\frac{x}{20}=\frac{x+400}{25}$

Solving for $x$

Multiplying both sides by 100 to remove fractions.

⇒ $100\times \frac{x}{20}=100\times \frac{x+400}{25}$

⇒ $5x=4(x+400)$

Using distribution.

⇒ $5x=4x+1600$

Subtracting both sides by $4x$

⇒ $5x-4x=4x-4x+1600$

⇒ $x=1600$

Thus, Distance traveled by Train W = 1600 miles

Distance traveled by Train Z = $1600+400$ = 2,000 miles

3 0

2 years ago

Decide, without calculation, if each of the integrals below are positive, negative, or zero. Let D be the region inside the unit

Schach [20]

The integrals over B and T will be positive. Keeping $y$ fixed, $xe^x$ is strictly increasing over D as $x$ increases, so the integrals over $x$ (i.e. the bottom/top left quadrants of D) is negative but the integrals over $x>0$ are *more* positive.

The integrals over R and L are zero. If we take $f(x,y)=xe^x$ , then $f(x,-y)=f(x,y)$ , which is to say $f$ is symmetric across the $x$ -axis. For the same reason, the integral over all of D is also zero.