Answer:
The revenue for Granton location is 175 thousand dollars
Step-by-step explanation:
Given
Cedarton 121
Rimber 189
Linton 147
Mean = 158
Required
Revenue for Granton location.
To calculate the revenue for Granton location, we make use of mean formula.
Mean is calculated by Summation of Observation divided by number of observations.
Since Granton location is unknown; Let it be represented by letter G.
So, the summation of observation becomes 121 + 189 + 147 + G
Summation = 457 + G
The number of observations = 4
Recall that Mean = Summation ÷ Number
By substituting 158 for mean, 457 + G for summation and 4 for number, we have
158 = (457 + G) ÷ 4
158 = ¼(457 + G)
Multiply both sides by 4
4 * 158 = = 4 * ¼(457 + G)
632 = 457 + G
Make G the subject of formula
G = 632 - 457
G = 175
Hence, the revenue for Granton location is 175 thousand dollars
Answer:
Therefore the y-intercept of the function is 4.
Step-by-step explanation:
Intercepts:
The line which intersect on x-axis and y-axis are called intercepts.
y-intercept: The line or function which intersect at y-axis. So when the line intersect at y-axis, X coordinate is zero.
So in the given Function Put x = 0 we will get the y-intercept

Put x =0


Therefore the y-intercept of the function is 4.
Answer: B) The heights of girls who live on a certain street in the city of Buffalo
Every answer choice starts with "the heights of all 14-year-old girls who", so we can ignore that part. Choice A describes the largest population while choice B describes the smallest population. In other words, choice A is very general and broad, while choice B is very specific and narrow. The more specific you get and the smaller the population is, the less likely its going to be normally distributed.
Answer:
- 880 lbs of all-beef hot dogs
- 2000 lbs of regular hot dogs
- maximum profit is $3320
Step-by-step explanation:
We can let x and y represent the number of pounds of all-beef and regular hot dogs produced, respectively. Then the problem constraints are ...
- .75x + 0.18y ≤ 1020 . . . . . . limit on beef supply
- .30y ≤ 600 . . . . . . . . . . . . . limit on pork supply
- .2x + .2y ≥ 500 . . . . . . . . . . limit on spice supply
And the objective is to maximize
p = 1.50x + 1.00y
The graph shows the constraints, and that the profit is maximized at the point (x, y) = (880, 2000).
2000 pounds of regular and 880 pounds of all-beef hot dogs should be produced. The associated maximum profit is $3320.