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Anuta_ua [19.1K]
2 years ago
8

Change the order or grouping to find sum, explain how you used properties to find sum. 63+86+77

Mathematics
1 answer:
ZanzabumX [31]2 years ago
6 0
63+86+77 it =s 226 so thank you for asking am only 9 am in 4 grade its easy look it up on the calculator but I did not use it believe me
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Of the following people in the concentration camp , who behaves kindly to wiesel and his father
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The answer is Bela Katz
4 0
2 years ago
How do you simplify (25/a -a l) / (5+a)
andrey2020 [161]

Simplify the following:

(25/a - a l)/(a + 5)


Put each term in 25/a - a l over the common denominator a: 25/a - a l = 25/a - (a^2 l)/a:

(25/a - (a^2 l)/a)/(a + 5)

25/a - (a^2 l)/a = (25 - a^2 l)/a:

Answer: ((25 - a^2 l)/a)/(a + 5)

7 0
2 years ago
Paulina is remodeling her bathroom. the tile she has chosen are squares and trapezoids. the side length of each square inthe til
NemiM [27]
Check the picture below.

is not very specific above, but sounds like it's asking for an equation for the trapezoid only, mind you, there are square tiles too.

but let's do the trapezoid area then, 

\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\

\bf A=\cfrac{h(a+b)}{2}\quad 
\begin{cases}
A=At\\
a=x\\
h=x\\
b=2x
\end{cases}\implies At=\cfrac{x(x+2x)}{2}
\\\\\\
At=\cfrac{x(3x)}{2}\implies At=\cfrac{3x^2}{2}\impliedby \textit{now, solving for \underline{x}}
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2At=3x^2\implies \cfrac{2At}{3}=x^2\implies \sqrt{\cfrac{2At}{3}}=x\implies \left( \frac{2At}{3} \right)^{\frac{1}{2}}=x

8 0
2 years ago
Sadie simplified the expression StartRoot 54 a Superscript 7 b cubed EndRoot, where a greater-than-or-equal-to 0, as shown colon
Nadusha1986 [10]

Answer:

Sadie's error is " she made error in step 2 =\sqrt{3^2\times 6\times a^2\times a^5\times b^2\times b}  where a\geqslant 0"

Because she made error in splitting the powers to simplify the square root

<h3>Therefore the correct answer for Sadie's expression is 3ab\sqrt{6ab} where a\geqslant 0</h3>

Step-by-step explanation:

Given that " Sadie simplified the expression StartRoot 54 a Superscript 7 b cubed EndRoot, where a greater-than-or-equal-to 0, "

It can be written as \sqrt{54a^7b^3} where a\geqslant 0

The given expression is \sqrt{54a^7b^3} where a\geqslant 0

To find Sadie's error and explain the correct answer :

Sadie's steps are

\sqrt{54a^7b^3}  where a\geqslant 0

=\sqrt{3^2\times 6\times a^2\times a^5\times b^2\times b}

=3ab\sqrt{6a^5b}

<h3>\sqrt{54a^7b^3}=3ab\sqrt{6a^5b} where a\geqslant 0</h3><h3><u>Now corrected steps are</u></h3>

\sqrt{54a^7b^3}  where a≥0

=\sqrt{(9\times 6)(a^{6+1})(b^{2+1})

=\sqrt{(3^2\times 6)(a^6.a^1)(b^2.b^1) (by using the identity a^{m+n}=a^m.a^n

=\sqrt{3^2\times 6\times ((a^3)^2.a)(b^2.b) (by using the identity a^{mn}=(a^m)^n )

=3ab\sqrt{6ab}

Therefore \sqrt{54a^7b^3}=3ab\sqrt{6ab}  where a\geqslant 0

<h3>The correct answer is 3ab\sqrt{6ab} where a\geqslant 0</h3>

Sadie's error is " she made error in step 2 =\sqrt{3^2\times 6\times a^2\times a^5\times b^2\times b} " where a\geqslant 0

Because she made error in splitting the powers to simplify the square root

<h3>Therefore the correct answer for Sadie's expression is 3ab\sqrt{6ab} where a\geqslant 0</h3>
5 0
1 year ago
Read 2 more answers
At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
2 years ago
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