Answer:
P(t) = 27000 * (1/9)^(t/4)
Step-by-step explanation:
This problem can me modelled with an exponencial formula:
P = Po * (1+r)^t
Where P is the final value, Po is the inicial value, r is the rate and t is the amount of time.
In this problem, we have that the inicial population/value is 27000, the rate is -8/9 (negative because the population decays), and the time t is in months, so as the rate is for every 4 months, we use the value (t/4) in the exponencial.
So, our function will be:
P(t) = 27000 * (1-8/9)^(t/4)
P(t) = 27000 * (1/9)^(t/4)
Answer:
Shift right by 4
Step-by-step explanation:
Given f(x)=x^2
g(x)= x^2-8x+16
Using
Horizontal Shift theorem dealing with the question
If the graph were to be move to to the right, we must use of graph f (x-L)
Where L= 4 and
NOTE:
POSITIVE L MAKES GRAPH SHIFT RIGHT
2) NEGATIVE MAKES GRAPH SHIFT LEFT
g(x)= x^2-8x+16
If we factorize this we have
(x-4)(x-4)
Since the two terms are the same we have (x-4)^2
Then it can move by factor of 4 to the right since constant 4 can be substracted from the parents function
Answer:
about 135 more miles to go
Step-by-step explanation:
Answer:
We have the functions:
f(x) = IxI + 1
g(x) = 1/x^3.
Now, we know that the composite functions do not permute.
How we can prove this?
First, two composite functions are commutative if:
f(g(x)) = g(f(x))
Well, you could use brute force (just replace the values and see if the composite functions are commutative or not)
But i will use a more elegant way.
We can notice two things:
g(x) has a discontinuity at x = 0.
so:
f(g(x)) = I 1/x^3 I + 1
still has a discontinuty at x = 0, but:
g(f(x)) = 1/( IxI + 1)^3
here the denominator is IxI + 1, is never equal to zero.
So now we do not have a discontinuity.
Then the composite functions can not be commutative.
Step-by-step explanation:
Beef = 12 * 8 (cause 25 * 8 = 200)
Beef = 96
Chicken = 8 * 8 (cause 25 * 8 = 200)
Chicken = 64
Pasta = 5 * 8 (cause 25 * 8 = 200)
Pasta = 40
Answer- C] There are 32 more students who want beef meal more than want a chicken meal
