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2 years ago

Write the coordinates of the vertices after a rotation of 180 degrees counterclockwise around the origin.

Mathematics

1 answer:

Umnica [9.8K]2 years ago

8 0

90 degrees you are looking to your side

180 degrees you are looking behind you

around origin of 0,0

the image is flipped into the negative world if it is in posiitve or vice versa

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A coffeehouse charges a flat rate,r, for each hour customer wants to use the internet. Enter an equation to express the total co

sweet-ann [11.9K]

Answer:

c=rt is the equation to express the total cost c to use the internet at the coffeehouse for t hours.

Step-by-step explanation:

Given A coffeehouse charges a flat rate, r for each hour customer wants to use the internet. we have to write the equation to express the total cost c to use the internet at the coffeehouse for t hours.

Charges of internet per hour = r

Total hour = t hours

Hence, Cost = (Charges per hour)(Total hours)

= $r\times t$

∴ c=rt

which is the linear equation to express the total cost c to use the internet at the coffeehouse for t hours.

5 0

2 years ago

Find the dimensions of a rectangle with area 512 m2 whose perimeter is as small as possible. (If both values are the same number

Masja [62]

Answer:

Step-by-step explanation:

Length the length and breadth of the rectangle be x and y.

Area of the rectangle A = Length * breadth

Perimeter P = 2(Length + Breadth)

A = xy and P = 2(x+y)

If the area of the rectangle is 512m², then 512 = xy

x = 512/y

Substituting x = 512/y into the formula for calculating the perimeter;

P = 2(512/y + y)

P = 1024/y + 2y

To get the value of y, we will set dP/dy to zero and solve.

dP/dy = -1024y⁻² + 2

-1024y⁻² + 2 = 0

-1024y⁻² = -2

512y⁻² = 1

y⁻² = 1/512

1/y² = 1/512

y² = 512

y = √512 m

On testing for minimum, we must know that the perimeter is at the minimum when y = √512

From xy = 512

x(√512) = 512

x = 512/√512

On rationalizing, x = 512/√512 * √512 /√512

x = 512√512 /512

x = √512 m

Hence, the dimensions of a rectangle is √512 m by √512 m

5 0

2 years ago

What is the following difference?

Svetllana [295]

Answer:

$-7ab\sqrt[3]{3ab^2}$

Step-by-step explanation:

Remove perfect cubes from under the radical and combine like terms.

$2ab\sqrt[3]{192ab^2}-5\sqrt[3]{81a^4b^5}=2ab\sqrt[3]{4^3\cdot 3ab^2}-5\sqrt[3]{(3ab)^3\cdot 3ab^2}\\\\=(8ab -15ab)\sqrt[3]{3ab^2}=\boxed{-7ab\sqrt[3]{3ab^2} }$

7 0

2 years ago

Evaluate the line integral by the two following methods. xy dx + x2y3 dy C is counterclockwise around the triangle with vertices

nadezda [96]

Answer:

$\frac{2}{3}$

Step-by-step explanation:

a) The first part requires that we use line integral to evaluate directly.

The line integral is

$\int_C xydx + {x}^{2} {y}^{3} dy$

where C is counterclockwise around the triangle with vertices (0, 0), (1, 0), and (1, 2)

The boundary of integration is shown in the attachment.

Our first line integral is

$L_1 = \int_ {(0,0)}^{(1,0)} xydx + {x}^{2} {y}^{3} dy$

The equation of this line is y=0, x varies from 0 to 1.

When we substitute y=0 every becomes zero.

$\therefore \: L_1 =0$

Our second line integral is

$L_2 = \int_ {(1,0)}^{(1,2)} xydx + {x}^{2} {y}^{3} dy$

The equation of this line is:

$x = 0 \implies \: dx = 0$

y varies from 1 to 2.

We substitute the boundary and the values to get:

$L_2 = \int_ {1}^{2}1 \cdot y(0) + {1}^{2} \cdot \: {y}^{3} dy$

$L_2 = \int_ {1}^2 {y}^{3} dy = \frac{8}{3}$

The 3rd line integral is:

$L_3 = \int_ {(1,2)}^{(0,0)} xydx + {x}^{2} {y}^{3} dy$

The equation of this line is

$y = 2x \implies \: dy = 2dx$

x varies from 0 to 1.

We substitute to get:

$L_3 = \int_ {1}^{0} x \cdot \: 2xdx + {x}^{2} {(2x)}^{3}(2 dx)$

$L_3 = \int_ {1}^{0} 8 {x}^{5} + 2 {x}^{2} dx = - 2$

The value of the line integral is

$L = L_1 + L_2 + L_3$

$L = 0 + \frac{8}{3} + - 2 = \frac{2}{3}$

b) The second part requires the use of Green's Theorem to evaluate:

$\int_C xydx + {x}^{2} {y}^{3} dy$

Since C is a closed curve with counterclockwise orientation, we can apply the Green's Theorem.

This is given by:

$\int_C \: Pdx +Q \: dy = \int \int_ R \: Q_y - P_x \: dA$

$\int_C \: xydx + {x}^{2} {y}^{3} \: dy = \int \int_ R \: 3 {x}^{2} {y}^{2} - y \: dA$

We choose our region of integration parallel to the y-axis.

$\int_C \: xydx + {x}^{2} {y}^{3} \: dy = \int_ 0^{1} \int_ 0^{2x} \: 3 {x}^{2} {y}^{2} - y \: dydx$

$\int_C \: xydx + {x}^{2} {y}^{3} \: dy = \int_ 0^{1} \: {x}^{2} {y}^{3} - \frac{1}{2} {y}^{2} |_ 0^{2x} dx$

$\int_C \: xydx + {x}^{2} {y}^{3} \: dy = \int_ 0^{1} \: 8{x}^{5} - 2 {x}^{2} dx = \frac{2}{3}$

8 0

2 years ago

In circle O, AC and BD are diameters.

Ronch [10]

Answer:

mArc A B = 120° (C)

Step-by-step explanation:

Question:

In circle O, AC and BD are diameters.

Circle O is shown. Line segments B D and A C are diameters. A radius is drawn to cut angle D O C into 2 equal angle measures of x. Angles A O D and B O C also have angle measure x.

What is mArc A B?

a)72°

b) 108°

c) 120°

d) 144°

Solution:

Find attached the diagram of the question.

Let P be the radius drawn to cut angle D O C into 2 equal angle measures of x

From the diagram,

m Arc AOC = 180° (sum of angle in a semicircle)

∠AOD + ∠DOP + ∠COP = 180° (sum of angles on a straight line)

x° +x° + x° =180°

3x = 180

x = 180/3

x = 60°

m Arc DOB = 180° (sum of angle in a semicircle)

∠AOB + ∠AOD = 180° (sum of angles on a straight line)

∠AOB + x° = 180

∠AOB + 60° = 180°

∠AOB = 180°-60°

∠AOB = 120°

mArc A B = 120°

5 0

2 years ago