Answer:
Alice reaches 11 metres below the centre as lowest height.
Step-by-step explanation:
Cosine is a bounded function between -1 and 1, so that the lowest height that Alice achieves in Ferris wheel is:

Where:
- Time, measured in seconds.
- Height with respect to centre, measured in metres.
If
, then:


Alice reaches 11 metres below the centre as lowest height.
Answer: The given triangle LMN is an obtuse-angled triangle.
Step-by-step explanation: We are given to use Pythagorean identities to prove whether ΔLMN is a right, acute, or obtuse triangle.
From the figure, we note that
in ΔLMN, LM = 5 units, MN = 13 units and LN = 14 units.
We know that a triangle with sides a units, b units and c units (a > b, c) is said to be
(i) Right-angled triangle if 
(ii) Acute-angled triangle if 
(iii) Obtuse-angled triangle if 
For the given triangle LMN, we have
a = 14, b = 13 and c = 5.
So,

Therefore, 
Thus, the given triangle LMN is an obtuse-angled triangle.
I'm pretty sure the answer is 9 mix spice, hope I helped!
<span>The <u>correct answer</u> is:
A) 60% ± 18%.
Explanation:
In a confidence interval, the margin of error is given by z*(</span>σ/√n<span>), where </span>σ<span> is the standard deviation and n is the sample size.
First we <u>find the value of z</u>:
We want a 95% confidence level; 95% = 95/100 = 0.95.
To find the z-score, we first subtract this from 1:
1-0.95 = 0.05.
Divide by 2:
0.05/2 = 0.025.
Subtract from 1 again:
1-0.025 = 0.975.
Using a z-table, we find this value in the middle of the table. The z-score that is associated with this value is 1.96.
Back to our formula for margin of error, we have 1.96(</span>σ<span>/</span>√n<span>). The larger n, the sample size, is, the larger its square root is. When we divide by a larger number, our answer is smaller; this gives us a smaller margin of error.
This means that if we had a small sample size, we would divide by a smaller number, making our margin of error larger. The largest margin of error we have in this question is 18%, so this is our correct answer.</span>