All transportation (bus, cab, train) are all similarly likely to be selected, and 1 of them must be selected at morning and evening, so we get: P (bus) = P (cab) = P (train) = 1/3. We also have P(no cab in evening) = P(no cab at morning) = 2/3
Now, P(using cab exactly once) = P(cab at morning and no cab in the evening) + P(no cab at morning and cab in the evening)
= P(cab, no cab) + P(no cab, cab)
= 1/3 * 2/3 + 2/3 * 1/3
= 2/9 + 2/9
= 4/9
Probability that Elizabeth uses a cab only once is 4/9.
Answer:
Upstream
5.2=(x-y)5
Downstream
5.2=(x+y)2.5
Step-by-step explanation:
I’ll try and help u in 6 years
Answer:
there are no signs between the x and y and constant
it could be
2x+5y=15
2x+5y=-15
-2x+5y=15
2x-5y=15
for ax+by=c, the equation of a line paralell to that is
ax+by=d where a=a, b=b, and c and d are constants
(for this answer, I'm going to use 2x+5y=15)
given 2x+5y=15, the equation of a line paralell to that is 2x+5y=d
to find d, subsitute the point (4,-2), basically put 4 in for x and -2 for y to get the constant
2x+5y=d
2(4)+5(-2)=d
8-10=d
-2=d
the eqaution is 2x+5y=-2 (Only if the original equation is 2x+5y=-15
pls mark me brainlest
The correct answer to this is:
Nonrandom and biased
<span>The method of Li’s sampling has a
tendency that some elements or portion in the population has no chance of
selection. Further, it was not stated which portion of the population she
obtained the sample thus we cannot accurately determine the probability of
selection. This kind of sampling results in a bias. A biased sampling is a type
of nonrandom sampling. </span>
