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AnnZ [28]
2 years ago
6

The function f(t) = 4t2 − 8t + 8 shows the height from the ground f(t), in meters, of a roller coaster car at different times t.

Write f(t) in the vertex form a(x − h)2 + k, where a, h, and k are integers, and interpret the vertex of f(t).f(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 2 meters from the groundf(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 4 meters from the groundf(t) = 4(t − 1)2 + 4; the minimum height of the roller coaster is 1 meter from the groundf(t) = 4(t − 1)2 + 4; the minimum height of the roller coaster is 4 meters from the ground
Mathematics
2 answers:
lidiya [134]2 years ago
8 0

Answer:

f(t) = 4(t − 1)2 + 4; the minimum height of the roller coaster is 4 meters from the ground

Step-by-step explanation:

The function is a quadratic where t is time and f(t) is the height from the ground in meters. You can write the function f(t) = 4t2 − 8t + 8 in vertex form by completing the square. Complete the square by removing a GCF from 4t2 - 8t. Take the middle term and divide it in two. Add its square. Remember to subtract the square as well to maintain equality.

f(t) = 4t2 − 8t + 8

f(t) = 4(t2 - 2t) + 8                                  The middle term is -2t

f(t) = 4(t2 - 2t + 1) + 8 - 4                        -2t/2 = -1; -1^2 = 1

f(t) = 4(t-1)^2 + 4                                      Add 1 and subtract 4 since 4*1 = 4.

The vertex (1,4) means at a minimum the roller coaster is 4 meters from the ground.

  • f(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 2 meters from the ground
  • f(t) = 4(t − 1)2 + 2; the minimum height of the roller coaster is 4 meters from the ground
  • f(t) = 4(t − 1)2 + 4; the minimum height of the roller coaster is 1 meter from the ground
  • f(t) = 4(t − 1)2 + 4; the minimum height of the roller coaster is 4 meters from the ground
vodka [1.7K]2 years ago
5 0

your answer would be the last one.

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Answer:

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From the question, we have the following values:

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Day 3

205.66 × 82% = 168.6412 cells

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Day 4

374.3012 × 82% = 306.926984 cells

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1239.8352949 × 82% = 1016.6649418 cells

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I'm pretty sure the answer will be 6/10





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Answer:

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<em>Equations </em>

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Let's cube both sides of the equation:

\left (\sqrt[3]{162x^cy^5}\right )^3=\left (3x^2y \sqrt[3]{6y^d}\right)^3

The left side just simplifies the cubic root with the cube:

162x^cy^5=\left (3x^2y \sqrt[3]{6y^d}\right)^3

On the right side, we'll simplify the cubic root where possible and power what's outside of the root:

162x^cy^5=3^3x^6y^3 (6y^d)

Simplifying

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Equating the powers of x and y separately we find

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LESSON 1 SESSION 1
denpristay [2]

Answer:

  • <em>Between which two tens does it fall?</em><em> </em><u>Between 25 and 26 tens</u>

<em><u /></em>

  • <em>Between which two hundreds does it fall?</em> <u>Between 2 and 3 hundreds</u>

Explanation:

The place-value chart is:

Hundreds         Tens      Ones

       2                   5             3

<em><u /></em>

<em><u>a)  Between which two tens does it fall? </u></em>

Using the place values you can write 253 = 25 × 10 + 3, i.e. 25 tens and 3 ones.

From that you can write:

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Then, you conclude that 253 is between 25 and 26 tens.

<u><em>b) Between which two hundreds does it fall?</em></u>

Using the same reasoning:

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Conclusion: 253 is between 2 hundreds and 3 hundreds.

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2 years ago
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