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Mariana [72]
2 years ago
11

Several batches of stew were made yesterday. Each batch required 1 and two-thirds pounds of meat. All together, 10 and StartFrac

tion 5 over 6 EndFraction pounds of meat was used. Janice tried to find the number of batches of stew made. Her work is shown below.
10 and StartFraction 5 over 6 EndFraction divided by 1 and two-thirds = StartFraction 65 over 6 EndFraction divided by five halves = StartFraction 65 over 6 EndFraction times StartFraction 2 over 5 EndFraction = StartFraction 130 over 30 EndFraction = 4 and one-third

When she checked the answer by estimating, it did not make sense. What error did Janice make?
Mathematics
2 answers:
Sav [38]2 years ago
8 0

Answer:

Step 2

1 2/3 was converted as 5/2 instead of 5/3

Step-by-step explanation:

  • Each batch = 1 2/3
  • Total = 10 5/6

<u>Number of batches </u>

  • 10 5/6 : 1 2/3 =
  • 65/6 : 5/3 =
  • 65/6 * 3/5 =
  • 65/10 =
  • 6.5

<u>Solution by Janice:</u>

  1. 10 5/6 : 1 2/3 =
  2. 65/6 : <u>5/2</u> =
  3. 65/6 * 2/5 =
  4. 130/30 =
  5. 4 1/3

<u>Error made at step 2:</u>

  • StartFraction 65 over 6 EndFraction divided by five halves = StartFraction 65 over 6 EndFraction times StartFraction 2 over 5

1 2/3 was converted as 5/2 instead of 5/3

LuckyWell [14K]2 years ago
8 0

Answer:

Step 2

Step-by-step explanation:

Got it right on the Edge test.

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The total weight of the three fishes is 8lb and 13oz

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2 years ago
One in a hundred million people is a genius. If they are a genius, the probability that the person is acting extremely quirky is
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Answer:

The correct option is E) About 1 in a million.

Step-by-step explanation:

Consider the provided information.

It is given that one in a hundred million people is a genius.

Let G represents the Genius and Q represents the quirky.

We need to find the probability that someone is acting quirky- what is the probability that they are a genius.

The probability that person is quirky is: P(Q)=0.999\cdot0.00000001+0.01\cdot0.99999999

The probability of P(Q\cap G)=0.999\cdot0.00000001

Hence, the required probability is:

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Assume the blood pressures of 10 people were measured before and after sleeping for the night. What is the corresponding critica
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Answer:

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And since we have a one tailed test we need to look in the t distribution with 9 degrees of freedom a quantile who accumulates 0.05 of the area on a tail and we got:

|t_{crit}| =1.833

Step-by-step explanation:

Previous concepts

A paired t-test is used to compare two population means where you have two samples in which observations in one sample can be paired with observations in the other sample. For example if we have Before-and-after observations (This problem) we can use it.  

Let put some notation  

x=test value with right arm , y = test value with left arm  

The system of hypothesis for this case are:  

Null hypothesis: \mu_y- \mu_x = 0  

Alternative hypothesis: \mu_y -\mu_x \neq 0  

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s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}  

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For the critical value we need to calculate the degrees of freedom given by:

df = n-1= 10-1=9

And since we have a one tailed test we need to look in the t distribution with 9 degrees of freedom a quantile who accumulates 0.05 of the area on a tail and we got:

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Answer:

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