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alexgriva [62]
2 years ago
9

Rectangle A’B’C’D is the imagine if rectangle ABCD after a dilation. The center of dilation is the orgin. What is the scale fact

or of the dilation?

Mathematics
1 answer:
Leokris [45]2 years ago
7 0

Answer:

D.  3

Step-by-step explanation:

Look at rectangle ABCD.  It's dimensions are 1 by 2 (1 unit high and 2 units long).  Now look at rectangle A'B'C'D', the image.  It's a rectangle that is 3 by 6.

The dimensions of the original rectangle have been multiplied by 3.

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anzhelika [568]

Answer:

A) 56 . . . . . . the (negative) sum of -7 and -49

b) 112 . . . . . the product of 7 and 16

c) 16 . . . . . . the square of 8/2

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Convert 778.5 million km to scientific notation.
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778.5 Million in Scientific Notation is..

7.785 × 10^{8}

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Explain how you can use the inscribed angle theorem to justify its second corollary, that an angle inscribed in a semicircle is
Katarina [22]
Prove:

The angle inscribed in a semicircle is a right angle. 

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Approximately 80,000 marriages took place in the state of New York last year. Estimate the probability that for at least one of
sasho [114]

Answer:

a)0,45119

b)1

Step-by-step explanation:

For part A of the problem we must first find the probability that both people in the couple have the same birthday (April 30)

P=\frac{1}{365} *\frac{1}{365}=\frac{1}{133225} \\

Now the poisson approximation is used

λ=nP=80000*1/133225=0,6

Now, let X be the number of couples that birth April 30

P(X ≥ 1) =

1 − P(X = 0) =

1-\frac{(e^-0.6)*(-0,6)^{0} }{0!}

P(X ≥ 1) = 0,45119

B)  Now want to find the

probability that both partners celebrated their birthday on th, assuming that the year is 52 weeks and therefore 52 thursday

P=52*\frac{1}{365} *\frac{1}{365}=\frac{52}{133225} \\

Now the poisson approximation is used

λ=nP=80000*52/133225=31.225

Now, let X be the number of couples that birth same day

P(X ≥ 1) =

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6 0
2 years ago
General Hospital has noted that they admit an average of 9 patients per hour.
serious [3.7K]

Answer:

(a) The probability that during the next hour less than 3 patients will be admitted is 0.00623.

(b) The probability that during the next two hours exactly 8 patients will be admitted is 0.00416.

Step-by-step explanation:

<u>The complete question is:</u> General Hospital has noted that they admit an average of 8 patients per hour.

(a) What is the probability that during the next hour less than 3 patients will be admitted?

(b) What is the probability that during the next two hours exactly 8 patients will be admitted?

The above situation can be represented through Poisson distribution as it includes the arrival rate of the pattern. So, the probability distribution of the Poisson distribution is given by;

P(X = x) = \frac{e^{-\lambda} \times \lambda^{x} }{x!} ; x = 0,1,2,......

Here X = Number of patients admitted in the hospital

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So, X ~ Poisson(\lambda = 9)

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    P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

                  = \frac{e^{-9} \times 9^{0} }{0!} + \frac{e^{-9} \times 9^{1} }{1!} + \frac{e^{-9} \times 9^{2} }{2!}

                  = e^{-9}  +(e^{-9} \times 9)+ \frac{e^{-9} \times 81}{2}

                  = <u>0.00623</u>

(b) Here, \lambda = 9 \times 2 = 18 because we have to find the probability for the next two hours and we are given in the question of per hour.

So, X ~ Poisson(\lambda = 18)

Now, the probability that during the next two hours exactly 8 patients will be admitted is given by = P(X = 8)

    P(X = 8) =  \frac{e^{-18} \times 18^{8} }{8!}

                  = <u>0.00416</u>

3 0
2 years ago
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