Answer:
The coefficients are
11,-4 and 0
Step-by-step explanation:
We are given two algebraic expressions. We are subtracting the second from the first.
First one is
Second expression is
The given expression
=
The coefficients are
11,-4 and 0
It will be a kid getting hit in the leg by the kids in the lunch table so it will be 4
Answer:
The number of different combinations of three students that are possible is 35.
Step-by-step explanation:
Given that three out of seven students in the cafeteria line are chosen to answer a survey question.
The number of different combinations of three students that are possible is given as:
7C3 (read as 7 Combination 3)
xCy (x Combination y) is defines as
x!/(x-y)!y!
Where x! is read as x - factorial or factorial-x, and is defined as
x(x-1)(x-2)(x-3)...2×1.
Now,
7C3 = 7!/(7 - 3)!3!
= 7!/4!3!
= (7×6×5×4×3×2×1)/(4×3×2×1)(3×2×1)
= (7×6×5)/(3×2×1)
= 7×5
= 35
Therefore, the number of different combinations of three students that are possible is 35.
Answer:
Step-by-step explanation:
This question is too difficult
