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Nonamiya [84]
2 years ago
8

Twenty people get into an elevator in a hotel with seven floors, and all of them get off at some point. How many different possi

bilities exist for how the people could get off the elevator? (you can treat the people as indistinguishable for this problem, i.e., for example, if two people get off on the 4th floor, we don’t care which two people they are.)
Mathematics
1 answer:
Fittoniya [83]2 years ago
7 0

Answer:

140

Step-by-step explanation:

you multiply the amount of people by the amount of floors, 7x20=140

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Answer:

See diagram attached.

Step-by-step explanation:

The line of reflection of preimage ABC reflected onto image A'B'C' can be found by the perpendicular bisector of lines joining the corresponding points of the image and preimage, for example, AA', or BB'.

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2 years ago
Which graph shows the solution to the system of linear inequalities? y ≥ 2x + 1 y ≤ 2x – 2
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Answer:

Step-by-step explanation:

Given the two inequalities:

y \ge 2x + 1\\ y \le 2x - 2

To graph them, first of all, let us write their corresponding equations:

y = 2x + 1 \\y = 2x - 2

We now find at least 2 points each which satisfy the equations to plot the graph.

Equation y = 2x + 1:

Putting x = 0, y = 1

Putting y = 0, x = -\frac{1}2.

Two points are (0, 1) and (-\frac{1}2, 0).

Equation y = 2x -2:

Putting x = 0, y = -2

Putting y = 0, x = 1.

Two points are (0, -2) and (1, 0).

Now, let us plot them.

Let us take a point (1, 4) and check whether it satisfies the first inequality.

4 \ge 2 \times 1 +1\\\Rightarrow 4 \ge 3

Which is true.

So, The shaded region will be <em>towards point (1,4).</em>

<em></em>

Let us take a point (1, 4) and check whether it satisfies the second inequality.

4 \le 2 \times 1 -2\\\Rightarrow 4 \le 0\ [\bold{False}]

So, The shaded region will be <em>opposite to point (1,4).</em>

Please refer to the attached graph for the answer.

<em>No solution exists for them because there is no common shaded region</em>.

3 0
2 years ago
The temperature at a point (x, y) on a flat metal plate is given by T(x, y) = 88/(2 + x2 + y2), where T is measured in °C and x,
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Answer:

D_uT(3,1)=-\frac{44}{9}*\frac{1}{\sqrt{2} } \approx-3.46

Step-by-step explanation:

To find the rate of change of temperature with respect to distance at the point (3, 1) in the x-direction and the y-direction we need to find the Directional Derivative of T(x,y). The definition of the directional derivative is given by:

D_uT(x,y)=T_x(x,y)i+T_y(x,y)j

Where i and j are the rectangular components of a unit vector. In this case, the problem don't give us additional information, so let's asume:

i=\frac{1}{\sqrt{2} }

j=\frac{1}{\sqrt{2} }

So, we need to find the partial derivative with respect to x and y:

In order to do the things easier let's make the next substitution:

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T(x,y)=88*u^{-1}

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T_x(x,y)=\frac{-176x}{(2+x^2+y^2)^2}

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Using the chain rule:

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Hence:

T_y(x,y)=88*(u^{-2})*\frac{\partial u}{\partial y}

Symplying the expression and replacing the value of u:

T_y(x,y)=\frac{-176y}{(2+x^2+y^2)^2}

Therefore:

D_uT(x,y)=(\frac{1}{\sqrt{2} } )*(\frac{-176x}{(2+x^2+y^2)^2} -\frac{176y}{(2+x^2+y^2)^2})

Evaluating the point (3,1)

D_uT(3,1)=(\frac{1}{\sqrt{2} } )*(\frac{-176(3)-176(1)}{(2+3^2+1^2)^2})=(\frac{1}{\sqrt{2} })* (-\frac{704}{144})=(\frac{1}{\sqrt{2} }) ( - \frac{44}{9})\approx -3.46

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