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aleksklad [387]

2 years ago

7

Jordan used the distributive property to write an expression that is equivalent to 6c – 48. 6c - 48 is equivalent to 6(c - 48) I

s Jordan's work correct? Choose the correct answer.

2 answers:

Katyanochek1 [597]2 years ago

8 0

It’s incorrect.

The correct answer is 6(c - 8)

slega [8]2 years ago

6 0

No, the distributive property means that you multiply the coefficient in front of the brackets with everything in the brackets. Or, a(b+c) is equal to ab+ac, not just ab+c or b+ac. Jordan multiplied only c by 6 and left the 48 as it is, which is wrong, because 6(c-48) would be equal to 6*c - 6*48, not just 6*c - 48. The correct answer would be 6(c-8) because 6*8=48.

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A person is watching a boat from the top of a lighthouse. The boat is approaching the lighthouse directly. When first noticed, t

maksim [4K]

Answer:

Boat traveled 553.24 feet towards the lighthouse.

Step-by-step explanation:

In the figure attached AB is the light house of height 200 feet.

Angle of depression of the boat from the top of a lighthouse = angle of elevation of the lighthouse from the boat = 14°52'

so 1' = $\frac{1}{60}$ degree

so angle of elevation at point C = 14 + $\frac{52}{60}$

So angle of elevation from C = (14 + 0.87) = 14.87°

Similarly, when boat arrives at point D angle of elevation = 45°10' = 45 + $\frac{10}{60}$ = 45.17°

Now we have to calculate the distance CD, traveled by the boat.

In ΔABC

tan14.87 = $\frac{200}{BC}$

0.2655 = $\frac{200}{BC}$

BC = $\frac{200}{0.26552}$

BC = 753.239 feet

Similarly in ΔABD

tan45.17 = $\frac{200}{BD}$

1 = $\frac{200}{BD}$

BD = 200 feet

So distance CD = BC - BD

CD = 753.239 - 200

= 553.24 feet

Therefore, Boat traveled 553.24 feet towards the lighthouse.

7 0

2 years ago

Read 2 more answers

The scale factor of a room for a scale drawing is 2.3. The actual length of a wall in the room is 46 feet and the actual width o

dimaraw [331]

Answer:

There's two ways to solve this.

Step-by-step explanation:

First way:

Let's divide the width and length by 2.3.

46÷2.3=20

69÷2.3=30

20×30

600 ft²

Second Way:

Let's find the area of the actual room.

46×69

3,174 ft²

Let's find the scale drawing squared.

2.3²=5.29

3,174÷5.29

600 ft²

3 0

2 years ago

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Find a polynomial function of degree 3 such that f(10)=17 and the zeros of f are 0, 5 and 8

fomenos

Step-by-step explanation:

Since f(0) = f(5) = f(8) = 0, we have f(x) = Ax(x - 5)(x - 8), where A is a real constant.

We know that f(10) = 17.

=> A(10)(10 - 5)(10 - 8) = 17

=> A(10)(5)(2) = 17

=> 100A = 17, A = 0.17.

Hence the answer is f(x) = 0.17x(x - 5)(x - 8).

3 0

1 year ago

Evaluate the function f(x) = –2x2 – 3x + 5 for the input value –3.

Novosadov [1.4K]

Just so u know, ur output value is f(x) and ur input value is x

f(x) = -2x^2 - 3x + 5....when ur input value(x) is -3

f(-3) = -2(-3^2) - 3(-3) + 5 =
f(-3) = -2(9) + 9 + 5
f(-3) = -18 + 14
f(-3) = -4 <==

4 0

1 year ago

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The United States Bureau of Labor Statistics (BLS) conducts the Quarterly Census of Employment and Wages (QCEW) and reports a va

Firlakuza [10]

Answer:

1

The probability is $P(\= X < 33) = 0.8531$

2

The probability is $P(\= X > 30) = 0.3520$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 28.29$

The standard deviation is $\sigma = 33.493$

The sample size is $n = 56$

Generally the standard error for the sample mean $(\= x )$ is mathematically evaluated as

$\sigma _{\=x} = \frac{\sigma}{\sqrt{n} }$

substituting values

$\sigma _{\=x} = \frac{33.493}{\sqrt{56} }$

$\sigma _{\=x} = 4.48$

Apply central limit theorem[CLT] we have that

$P(\= X < 33) = [z < \frac{33 - \mu }{\sigma_{\= x}} ]$

substituting values

$P(\= X < 33) = [z < \frac{33 - 28.29 }{4.48} ]$

$P(\= X < 33) = [z < 1.05 ]$

From the z-table we have that

$P(\= X < 33) = 0.8531$

For the second question

Apply central limit theorem[CLT] we have that

$P(\= X > 30 ) = [z > \frac{30 - \mu }{\sigma_{\= x}} ]$

substituting values

$P(\= X < 33) = [z > \frac{30 - 28.29 }{4.48} ]$

From the z-table we have that

$P(\= X < 30) = 0.6480$

Thus

$P(\= X > 30) = 1- P(\= X < 30) = 1- 0.6480$

$P(\= X > 30) = 0.3520$

3 0

2 years ago