Answer:
7.5
Step-by-step explanation:
106% of $x = $7.95
In other words,
![\[\frac{106}{100}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B106%7D%7B100%7D%5C%5D)
of $x = 7.95
Multiplying both sides of the equation by ![\[\frac{100}{106}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B100%7D%7B106%7D%5C%5D)
![\[\frac{106}{100} * \frac{100}{106}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B106%7D%7B100%7D%20%2A%20%5Cfrac%7B100%7D%7B106%7D%5C%5D)
of x = 7.95 * ![[\frac{100}{106}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B100%7D%7B106%7D%5D)
=> x = ![[\frac{750}{100}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B750%7D%7B100%7D%5D)
=> x = ![[\frac{7.50}{1}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B7.50%7D%7B1%7D%5D)
=> x = 7.5
Validation: 106% of 7.5 = 7.95
△RST is dilated with the rule DT,1/3 (x, y), where the center of dilation is T(3, –2).
The distance between the x-coordinates of R and T is 3 .
The distance between the y-coordinates of R and T is 6.
R' is 1 unit left,2 units up from T, so the coordinates of R' are (2,0)
The solution exist for the given equation are
x=-2
and
x=11/3
Answer:
1/9
Step-by-step explanation:
135 in Sport centre: Total
59:swimming pool
31:track
19 both swimming and gym
16 gym and track
4 all three facilities
4 people use all three facilities, then
16 - 4 = 12 people use the gym and the track and do not use the pool;
9 - 4 = 5 people use the pool and the track and do not use the gym;
19 - 4 = 15 people use the gym and the pool and do not use the track.
At least two facilities use 4 + 12 + 5 + 15 = 36 people, 4 of them use all three facilities. Thus, the probability that a randomly selected person which uses at least two facilities, uses all the facilities is
4/36=1/9
Hope this helps!!!
Answer:
Step-by-step explanation:
a )
sample mean = sum total of given data / no of data
= 415.35 / 20 = 20.76
To calculate the median we arrange the data in ascending order and take the average of 10 th and 11 th term .
= 20.50 + 20.72 / 2
= 20.61
b ) To calculate the 10% trimmed mean , we neglect the largest 10% and smallest 10 % data and then calculate the mean . Here we neglect the first two smallest and last two greatest
(18.92 + 19.25 ..... + 22.43 + 22.85) / 16
= 20.74
c )
We can easily plot the data on number line from 17 to 24
d )
Maximum value of data set = 23.71 and minimum value is 18.04
mean is 20.76 , median is 20.61 and trimmed mean is 20.74
They are between maximum and minimum values of given data . Hence there is no outliers .
