Answer:
The probability that all three have type B+ blood is 0.001728
Step-by-step explanation:
For each person, there are only two possible outcomes. Either they have type B+ blood, or they do not. The probability of a person having type B+ blood is independent of any other person. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
The probability that a person in the United States has type B+ blood is 12%.
This means that 
Three unrelated people in the United States are selected at random.
This means that 
Find the probability that all three have type B+ blood.
This is P(X = 3).
The probability that all three have type B+ blood is 0.001728
If the coin is fair, the probability of a success on each roll is 0.5.
For this case we have the following expression:
The first step is to solve the quadratic term.
We have then:
Then, the second step is to subtract both resulting numbers:
We observe that the result obtained is a negative number.
Answer:
The result of the expression is given by:
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Answer with explanation:</h2><h2>
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The x% confidence interval interval interprets that we are x% confident that the true population mean falls in it.
Given : The owners of an amusement park computed a 90% confidence interval for the number of patrons with annual passes who visit the park daily.
Then, the correct interpretation of 90% confidence interval of (35, 51) will be that owners of an amusement park are 90% confident that the true population mean of the number of patrons with annual passes who visit the park daily lies in it.
