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Aleksandr [31]
2 years ago
10

A new car is purchased for 20300 dollars. The value of the car depreciates at 9.5% per year. What will the value of the car be,

to the nearest cent, after 11 years?
Mathematics
1 answer:
Iteru [2.4K]2 years ago
6 0
The starting value is 20,300, and the value is decreasing by 9.5% each year.

Because it decreases by 9.5% each year based on the previous amount, we use an exponential decay model.

A decrease by 9.5% corresponds to multiplying by 91.5% each year.

We write . We plug in 11 years for t.

A(t)=23000(0.915)^{t}\\\\A(11)=23000(0.915)^{11}\\\\A(11)=7671.18

$7,671.18
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Answer:

<u>Properties that are present are </u>

Property I

Property IV

Step-by-step explanation:

The function given is  y=b^x  where b > 1

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Let's check the conditions:

I. As the x-values increase, the y-values increase.

Let's put some values:

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II. The point (1,0) exists in the table.

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III. As the x-value increase, the y-value decrease.

We have already seen that as x increase, y also increase in part I.

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IV. as the x value decrease the y values decrease approaching a singular value.

THe exponential function of this form NEVER goes to 0 and is NEVER negative. So as x decreases, y also decrease and approached a value (that is 0) but never becomes 0.

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Option I and Option IV are true.

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