Answer: The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is 0.596
Step-by-step explanation:
Since the weights of catfish are assumed to be normally distributed,
we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = weights of catfish.
µ = mean weight
σ = standard deviation
From the information given,
µ = 3.2 pounds
σ = 0.8 pound
The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is is expressed as
P(x ≤ 3 ≤ 5.4)
For x = 3
z = (3 - 3.2)/0.8 = - 0.25
Looking at the normal distribution table, the probability corresponding to the z score is 0.401
For x = 5.4
z = (5.4 - 3.2)/0.8 = 2.75
Looking at the normal distribution table, the probability corresponding to the z score is 0.997
Therefore,.
P(x ≤ 3 ≤ 5.4) = 0.997 - 0.401 = 0.596
I believe the answer would be 49.64 because if you add them together 22.65+33.31 = 55.96 x .10 = 5.60 55.96-5.60 = $49.64
A sideways opening parabola is in the form
, so we know from the process of elimination that it will either be b or c. Next we have to realize that if the parabola opens to the left it is a negative parabola, just like if a parabola opens upside down it is a negative parabola. So the one that has the negative out front is b.
Answer/Step-by-step explanation:
The ratio of the enlargement to the original = A'E' to AE = A'E':AE = A'E'/AE
AE = 2.5
A'E' = 4
Ratio of the enlargement to the original = 4:2.5 = 1.6:1
To convert to percentage, divide 4 by 2.5 and multiply by 100.
Answer:
Vijay present age: a
Gautam present age : b
2/3=a/b
3a = 2b
3/4 = (a+5)/(b+5)
4a+20 = 3b +15
(3a - 2b =0) x 3---------9a - 6b = 0
(4a - 3b = -5) x 2------- 8a - 6b = -10
9a - 6b - 8a + 6b = 10
a = 10
3(10) - 2b =0
-2b = -30
b = 15
So
Vijay present age = 10
Gautam present age = 15
