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natka813 [3]
2 years ago
9

How many times greater is the value of the digit 8 in 82.77 than the value of the digit 8 in 20.18

Mathematics
1 answer:
Kitty [74]2 years ago
3 0

Answer:

Option 3. 1,000 times

Step-by-step explanation:

we know that

The value of digit 8 in 82.77 is equal to 80

The value of digit 8 in 20.18 is 0.08

so

Divide 80 by 0.08

80/0.08=1,000 times

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You know that the current exchange rate for US dollars (USD) to Indian rupees (INR) is 1:45.85, that the exchange rate for India
dem82 [27]

Answer:

C

Step-by-step explanation:

the answer on edgeunity

3 0
2 years ago
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A researcher found a study relating the value of a car, y, to the age of the car, x. When researchers looked at the association
vredina [299]

Answer: c) About 16% of the variation in value of the car is explained by a linear relationship with the age of the car.

e) The correlation coefficient, r, is 0.397.

Step-by-step explanation:

Given that:

Coefficient of determination (r²) between two variables, age of car (x) and value of car (y) = 0.158

Correlation of determination (r²) of 0.158 = (0.158 × 100% = 15.8% of the variation between the two variables can be explained by the regression line). Hence, about 16% of the variation between age and value of car can be explained by the linear relationship.

Coefficient of correlation (r) = sqrt(r²) = sqrt(0.158) = 0.397

8 0
2 years ago
A circle with radius of \greenD{5\,\text{cm}}5cmstart color #1fab54, 5, start text, c, m, end text, end color #1fab54 sits insid
Marat540 [252]

Answer:

The area of the shaded region is 42.50 cm².

Step-by-step explanation:

Consider the figure below.

The radius of the circle is, <em>r</em> = 5 cm.

The sides of the rectangle are:

<em>l</em> = 11 cm

<em>b</em> = 11 cm.

Compute the area of the shaded region as follows:

Area of the shaded region = Area of rectangle - Area of circle

                                            =[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50

Thus, the area of the shaded region is 42.50 cm².

7 0
2 years ago
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Using the midpoint method, find the cross-price elasticity of demand for FedEx and UPS overnight shipping if the price of FedEx
IrinaK [193]

Answer:

Cross price elasticity using midpoint method = 0.56

Step-by-step explanation:

Using the mid-point method

Cross-price Elasticity of Demand = <u>% change in Quantity demanded of UPS</u>

                                                          % change of price of FedEx

%change in Quantity demanded of UPS

using Mid-point method                          = <u> Q2-Q1           </u>  × 100

                                                                     (Q1+Q2)÷ 2

                                      = <u>1.3-1.2           </u>   × 100

                                        (1.2+1.3)÷2

                                     = <u>0.1      </u> × 100

                                       1.25

                                     = 8%

% change in price of FedEx

using midpoint method    =<u> P2-P1            </u>× 100

                                             (P1+P2)÷ 2

                                          =<u> 75-65           </u>× 100

                                            (65+75)÷2

                                          =<u> 10  </u>   × 100

                                             70

                                          = 14.28%

Cross-price Elasticity of Demand =  8% ÷ 14.28%

using midpoint method                = 0.56

             

6 0
1 year ago
World wind energy generating1 capacity, W , was 371 gigawatts by the end of 2014 and has been increasing at a continuous rate of
Sunny_sXe [5.5K]

Answer:

a) W(t) = 371(1.168)^{t}

b) Wind capacity will pass 600 gigawatts during the year 2018

Step-by-step explanation:

The world wind energy generating capacity can be modeled by the following function

W(t) = W(0)(1+r)^{t}

In which W(t) is the wind energy generating capacity in t years after 2014, W(0) is the capacity in 2014 and r is the growth rate, as a decimal.

371 gigawatts by the end of 2014 and has been increasing at a continuous rate of approximately 16.8%.

This means that

W(0) = 371, r = 0.168

(a) Give a formula for W , in gigawatts, as a function of time, t , in years since the end of 2014 . W= gigawatts

W(t) = W(0)(1+r)^{t}

W(t) = 371(1+0.168)^{t}

W(t) = 371(1.168)^{t}

(b) When is wind capacity predicted to pass 600 gigawatts? Wind capacity will pass 600 gigawatts during the year?

This is t years after the end of 2014, in which t found when W(t) = 600. So

W(t) = 371(1.168)^{t}

600 = 371(1.168)^{t}

(1.168)^{t} = \frac{600}{371}

(1.168)^{t} = 1.61725

We have that:

\log{a^{t}} = t\log{a}

So we apply log to both sides of the equality

\log{(1.168)^{t}} = \log{1.61725}

t\log{1.168} = 0.2088

0.0674t = 0.2088

t = \frac{0.2088}{0.0674}

t = 3.1

It will happen 3.1 years after the end of 2014, so during the year of 2018.

7 0
2 years ago
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