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slamgirl [31]
2 years ago
13

A company wants to establish that the mean life of its batteries, when used in a wireless mouse, is over 183 days. The data will

consist of the life lengths of batteries in 64 different wireless mice.
a) Formulate the null and alternative hypotheses.

b) If the true mean is 190 days, what error can be made?
Mathematics
1 answer:
enyata [817]2 years ago
4 0

Answer:

a) Null and alternative hypotheses are:

H_{0}: mu=183 days

H_{a}: mu>183 days

b) If the true mean is 190 days, Type II error can be made.

Step-by-step explanation:

Let mu be the mean life of the batteries of the company when it is used in a wireless mouse

Null and alternative hypotheses are:

H_{0}: mu=183 days

H_{a}: mu>183 days

Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.

That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.

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Option 4: \sqrt[7]{125x^9y^{12}} is the right answer

Step-by-step explanation:

Given expression is:

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In order to convert an exponent into radical form, the power should be in the form of 1/x where x is any number

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The 1/7 will be converted into base of radical while 3 will be he exponent

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Multiplying exponents

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Hence,

Option 4: \sqrt[7]{125x^9y^{12}} is the right answer

Keywords: Radicals, Exponents

Learn more about exponents at:

  • brainly.com/question/4939434
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#LearnwithBrainly

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Answer:

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Answer:

Step-by-step explanation:

* Lets explain how to find the probability of an event  

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