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slamgirl [31]
2 years ago
13

A company wants to establish that the mean life of its batteries, when used in a wireless mouse, is over 183 days. The data will

consist of the life lengths of batteries in 64 different wireless mice.
a) Formulate the null and alternative hypotheses.

b) If the true mean is 190 days, what error can be made?
Mathematics
1 answer:
enyata [817]2 years ago
4 0

Answer:

a) Null and alternative hypotheses are:

H_{0}: mu=183 days

H_{a}: mu>183 days

b) If the true mean is 190 days, Type II error can be made.

Step-by-step explanation:

Let mu be the mean life of the batteries of the company when it is used in a wireless mouse

Null and alternative hypotheses are:

H_{0}: mu=183 days

H_{a}: mu>183 days

Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.

That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.

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Bonnie is making a dipping sauce. She mixes 150 milliliters of soy sauce with 100 milliliters of vinegar. How much soy sauce doe
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We have been given that Bonnie is making a dipping sauce. She mixes 150 milliliters of soy sauce with 100 milliliters of vinegar.

1. We can find amount of soy sauce Bonnie mixes with every 1 milliliter of vinegar by dividing total amount of soy sauce by total amount of vinegar.

\text{Amount of soy sauce per ml vinegar}=\frac{150}{100}

\text{Amount of soy sauce per ml vinegar}=\frac{15}{10}=\frac{3}{2}

\text{Amount of soy sauce per ml vinegar}=1.50  

Therefore, Bonnie mixes 1.50 ml of soy sauce with every 1 ml of vinegar.

2. We can find amount of vinegar Bonnie mixes with every 1 ml of soy sauce by dividing total amount of vinegar by total amount of soy sauce.

\text{Amount of vinegar per ml soy sauce}=\frac{100}{150}

\text{Amount of vinegar per ml soy sauce}=\frac{10}{15}=\frac{2}{3}

\text{Amount of vinegar per ml soy sauce}=0.6666666666666667\approx0.67

Therefore, Bonnie mixes 0.67 ml of vinegar with every 1 ml of soy sauce.

7 0
2 years ago
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Two kilograms of ground cinnamon is packaged into bags containing 38 g each. There will also be some cinnamon left over. How man
Troyanec [42]
I think about 52 bags
2 kilometers = 2,000 grams
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2 years ago
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Triangle A and triangle B are drawn on the grid. Describe fully the single transformation which maps triangle A onto triangle B.
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Answer:

Step-by-step explanation:

Triangle A, transforms into a smaler size, and goes into full shape. Triangle B, goes into the negative numbers.

7 0
1 year ago
In the expression " 5.3t - (20÷4) + 11" what part is a quotient? Describe its parts.​
enyata [817]

Answer:

(20 divided by 4) is the quotient

Step-by-step explanation:

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A theatre has the capacity to seat people across two levels, the Circle and
andriy [413]

Answer: 76.19\%

Step-by-step explanation:

<h3> The complete exercise is: " A theatre has the capacity to seat people across two levels, the Circle, and the stalls. The ratio of the number of seats in the circle to a number of seats in the stalls is 2:5. Last Friday, the audience occupied all the 528 seats in the circle and \frac{2}{3} of the seats in the stalls. What is the percentage of occupancy of the theatre last Friday?"</h3>

Let be "s" the total number of seats in the Stalls.

The problem says that the ratio of the number of seats in the Circle to the number of seats in the Stalls is 2:5.

Since the number of seats that were occupied last Friday was 528 seats, we can set up the following proportion:

\frac{2}{5}=\frac{528}{s}

Solving for "s", we get:

s*\frac{2}{5}=528\\\\s=528*\frac{5}{2}\\\\s=1,320

So the sum of the number of seats in the Circle and the number of seats in the Stalls, is:

Total=1,320\ seats+528\ seats=1,848\ seats

 We know that \frac{2}{3} of the seats in the Stalls were occupied. Then, the number of seat in the Stalls that were occupied is:

(1,320)(\frac{2}{3})=880

Therefore, the total number of seats that were occupied las Friday is:

Total\ occupied=880\ seats+528\ seats=1,408\ seats

Knowing this, we can set up the following proportion, where "p" is the the percentage of occupancy of the theatre last Friday:

\frac{100}{1,848}=\frac{p}{1,408}

Solving for "p", we get:

(1,408)(\frac{100}{1,848})=p\\\\p=76.19\%

8 0
1 year ago
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