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erastovalidia [21]
2 years ago
8

Gary buys a 3 1/2 pound bag of cat food every 3 weeks. Gary feeds his cat the same amount of food each day. Which expression can

Gary use to determine the number of pounds of cat food his cat eats each year? (1 year = 52 weeks)
A. 7/2 x 52/3
B. 7/2 x 3/52
C. 3 ( 1/2 x 3/52
D. 3 ( 1/2 x 52/3 )
Mathematics
1 answer:
Ludmilka [50]2 years ago
8 0
D is the answer jdjjdjdkdkdkdkdkkdjd
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The quality control manager at a light bulb factory needs to estimate the mean life of a batch (population) of light bulbs. We a
Nadusha1986 [10]

Answer:

<em>a)95%  confidence intervals for the population mean of light bulbs in this batch</em>

(325.5 ,374.5)

b)

<em>The calculated value Z = 4 > 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>The manufacturer has not right to take the average life of the light bulbs is 400 hours.</em>

Step-by-step explanation:

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

The tabulated value Z₀.₉₅ = 1.96

<em>95%  confidence intervals for the population mean of light bulbs in this batch</em>

<em></em>(x^{-} - Z_{\frac{\alpha }{2} } \frac{S.D}{\sqrt{n} } , x^{-} + Z_{\frac{\alpha }{2} }\frac{S.D}{\sqrt{n} } )<em></em>

<em></em>(350 - 1.96\frac{100}{\sqrt{64} } , 350 + 1.96\frac{100}{\sqrt{64} } )<em></em>

(350 -24.5, 350 +24.5)

(325.5 ,374.5)

b)

<u><em>Explanation</em></u>:-

Given mean of the Population μ = 400

Given sample size n = 64

Given  mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

<u><em>Null hypothesis</em></u> : H₀:The manufacturer has right to take the average life of the light bulbs is 400 hours.

μ = 400

<u><em>Alternative Hypothesis: H₁:</em></u> μ ≠400

<u><em>The test statistic </em></u>

Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }

Z = \frac{350 -400}{\frac{100}{\sqrt{64} } }

|Z| = |-4|

The tabulated value   Z₀.₉₅ = 1.96

The calculated value Z = 4 > 1.96 at 0.05 level of significance

Null hypothesis is rejected.

<u><em>Conclusion:</em></u>-

The manufacturer has not right to take the average life of the light bulbs is 400 hours.

5 0
2 years ago
Jack bought 4 dozen eggs at $10 per dozen. 6 were broken. what percent of his money goes to waste
Korvikt [17]

So, if he has 4 dozen eggs, ten dollars per dozen, he has spent $40 on 48 eggs. <em>This means the cost of one egg = 48/40. </em>This can simplify to <em>6/5 </em>which is equal to<em> $1.20. </em>This means the value of one egg is $1.20, including the broken ones! So if six were broken, we multiply 1.20 x 6 which equals <em>$7.20!</em>

Use this "formula" to help find percentages

<em>Part/Total = %( Percentage )/ 100</em>

Now that we know how much money has gone to waste, we can plug in the known values into this "formula."

<em>7.2/48 = x/100</em>

Solve accordingly; cross multiply, 720 = 48x; divide both sides of the equation by 48 to isolate the variable, 720/48 = 48x/48; now you have your final answer which is:

15 = x; going back to the "formula" this means 15% of his money has gone to waste. I hope this helped! :)

5 0
2 years ago
find the scale, k, of H(3,4) if H'(9,12) after going through the transformation (x,y) ---&gt; (kx,ky) centered at the origin
stiks02 [169]

The value of scale k is 3

Step-by-step explanation:

In order to find the scale , we can either divide the coordinates of H' by the original point or compare both the points to find the original ordered pair.

Given

H(3,4)

H'(9,12)

The coordinates of H are multiplied with some integer k to form H'

So,

<u>For x-coordinate:</u>

3k = 9

k = 9/3 = 3

<u>For y-coordinate:</u>

4k = 12

k = 12/4 = 3

Hence,

The value of scale k is 3

Keywords: Coordinate geometry, scaling

Learn more about scaling at:

  • brainly.com/question/4771355
  • brainly.com/question/4786449

#LearnwithBrainly

5 0
2 years ago
Find the volume of the composite solid. Round to the nearest tenths. Radius:2 height:4
yKpoI14uk [10]

Answer:

60

Step-by-step explanation:

6 0
2 years ago
Compare the process of solving |x – 1| + 1 &lt; 15 to that of solving |x – 1| + 1 &gt; 15.
kicyunya [14]
In the first case we'd subtract 1 from both sides, obtaining |x-1|<14.

In the second case we'd also subtract 1 from both sides, and would obtain
 |x-1|>14.

What would the graphs look like?

In the first case, the graph would be on the x-axis with "center" at x=1.  From this center count 14 units to the right, and then place a circle around that location (which would be at x=15).  Next, count 14 units to the left of this center, and place a circle around that location (which would be -13).  Draw a line segment connecting the two circles.  Notice that all of the solutions are between -13 and +15, not including these endpoints.

In the second case, x has to be greater than 15 or less than -13.  Draw an arrow from x=1 to the left, and then draw a separate arrow from 15 to the right.  None of the values in between are solutions.

4 0
2 years ago
Read 2 more answers
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