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kakasveta [241]
2 years ago
7

If ƒ(x ) = 3x + 1 and and ƒ -1 = , then the ordered pair of ƒ -1(10) = (10, 31) (10, 3) (3, 10)

Mathematics
1 answer:
MAXImum [283]2 years ago
6 0
        f(x) = 3x + 1
           y = 3x + 1
      y - 1 = 3x + 1 - 1
      <u>y - 1</u> = <u>3x</u>
         3       3
¹/₃y - ¹/₃ = x
           y = ¹/₃x - ¹/₃
      f⁻¹(x) = ¹/₃x - ¹/₃
    f⁻¹(10) = ¹/₃(10) - ¹/₃
    f⁻¹(10) = 3¹/₃ - ¹/₃
    f⁻¹(10) = 3
It is equal too (10, 3).
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gregori [183]

Answer:

probability that all of the sprinklers will operate correctly in a fire: 0.0282

Step-by-step explanation:

In order to solve this question we will use Binomial  probability distribution because:

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A binomial distribution is a probability of a success or failures outcomes in an  repeated multiple or n times.

Number of outcomes of this distributions are two.

The formula is:

b(x; n, P) = C_{n,x}*p^{x}  * (1 - p)^{n-x}

b = binomial probability  also represented as P(X=x)

x =no of successes

P = probability of a success on a single trial

n = no of trials

C_{n,x} is calculated as:

C_{n,x} = n! / x!(n – x)!

        = 10!  / 10!(10-10)!

        = 1

According to given question:

probability of success i.e. p = 0.7 i.e. probability of a sprinkler to activate correctly.

number of trials i.e. n = 10 as number of sprinklers are 10

To find: probability that all of the sprinklers will operate correctly in a fire

X = 10 because we have to find the probability that "all" of the sprinklers will operate correctly and there are 10 sprinklers so all 10 of them

So putting these into the formula:

P(X=x) = C_{n,x}*p^{x}  * (1 - p)^{n-x}

           = C₁₀,₁₀ * 0.7¹⁰ * (1-0.7)¹⁰⁻¹⁰

           =  1 * 0.0282 * (0.3) ⁰

           = 1 * 0.0282 * 1

  P(X=x)        = 0.0282

5 0
1 year ago
Large flower pots weigh 28 pounds each.
LiRa [457]

Answer:

The correct answer is: 980 pounds

Step-by-step explanation:

1 flower pot = 28 pounds

1 crate = 35 pots

∴ 1 crate = 35 pots × 28 pounds = 980 pounds

5 0
1 year ago
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The dot plots below show rainfall totals in the Highlands and Lowlands areas of a certain region.
Andre45 [30]

Options:

A. Both the Highlands and the Lowlands data points are evenly distributed around the center.

B. Both the Highlands and the Lowlands data points are clustered toward the left of the plot.

C. The Highlands data points are evenly distributed around the center, while the Lowlands data points are clustered toward the left of the plot.

D. The Highlands data points are clustered toward the left of the plot, while the Lowlands data points are evenly distributed.

Answer:

B. Both the Highlands and the Lowlands data points are clustered toward the left of the plot.

Step-by-step Explanation:

From the dot plots displaying rainfall totals for highland and lowland areas as shown in the diagram attached below, we can clearly observe that most of the dots on the plot tend to be more concentrated towards the left of the plot, compared to the concentration of dots toward the right of the plot.

Invariably, we can infer that data points for lowlands and Highlands are clustered toward the left of the plot.

Therefore, the statement that is true, comparing the shapes of the dot plot is B. "Both the Highlands and the Lowlands data points are clustered toward the left of the plot."

7 0
2 years ago
Which equation can be used to find the length of Line segment A C? Triangle A B C is shown. Angle A C B is 90 degrees and angle
taurus [48]

<u><em>Answer:</em></u>

AC = 10sin(40°)

<u><em>Explanation:</em></u>

The diagram representing the question is shown in the attached image

Since the given triangle is a right-angled triangle, we can apply the special trig functions

<u>These functions are as follows:</u>

sin(θ) = opposite / hypotenuse

cos(θ) = adjacent / hypotenuse

tan(θ) = opposite / adjacent

<u>Now, in the given diagram:</u>

θ = 40°

AC is the side opposite to θ

AB = 10 in is the hypotenuse

<u>Based on these givens</u>, we will use the sin(θ) function

<u>Therefore:</u>

sin(40) = \frac{AC}{10}\\ \\AC = 10sin(40)

5 0
2 years ago
Read 2 more answers
Compute the integral (a) int sin (pi x) dx by letting u = pi x. (b) int e^(x/2) dx by letting u = x/2. Show that you got the cor
Maslowich

Answer:

(a) \int sin(\pi x) dx=-\frac {cos \pi x}{\pi}+c

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Step-by-step explanation:

(a)

\int sin(\pi x) dx

Let u = π x

differentiating with respect to x

du = π dx

\Rightarrow dx=\frac{du}{\pi}

Putting the value of x and dx

=\int sin u \frac{du}{\pi}

=\frac{-cos u}{\pi}+c    [ c is an arbitrary constant]

Now putting the value of u

=-\frac {cos \pi x}{\pi}+c  

(b)

\int e^\frac{x}{2} dx

Let u=\frac{x}{2}

differentiating with respect to x

du= \frac{1}{2} dx

2du = dx

Putting the value of x and dx

=\int e^u.2.du

=2e^u +c

Now putting the value of u

=2e^\frac{x}{2}+c       [ c is an arbitrary constant]

3 0
1 year ago
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