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vladimir2022 [97]
2 years ago
14

Beach Cruises prints brochures and fliers to advertise their dolphin watching tours. To print, the brochure requires three pages

while the flier requires two. They are limited to 500 sheets of paper, but need to print at least 80 brochures and 100 fliers. Each brochure cost 10 cents to print and each flier cost 6 cents to print. How many of each should their print to minimize their cost? Organize and show all work to support your final answer. Give a written summery at the end with your recommendation.
Mathematics
1 answer:
Ivanshal [37]2 years ago
3 0

Answer:

To minimize their costs, Beach Cruises should print 80 brochures and 130 fliers.

Step-by-step explanation:

Total number of sheets available = 500 sheets

For brochures;

1 brochure contains 3 pages

Minimum number of brochures that should be printed = 80

Cost of 1 brochure = 10 cents

Number of sheets required to print 80 brochures = 80 × 3 = 240 sheets

For fliers;

1 flier contains 2 pages

Minimum number of fliers to be printed = 100

cost of 1 flier = 6 cents

Number of sheets required to print 100 fliers = 100 × 2 = 200 sheets

Total number of sheets that will be used to print at least 80 brochures and 100 fliers = 240 + 200 = 440 sheets

number of sheets left = 500 - 440 = 60 sheets

After Beach cruises have printed the minimum required 80 brochures and 100 fliers, they are left with 60 free sheets of paper.

Since it is cheaper for Beach cruises to print fliers (at 6 cent per flier) than brochures (at 10 cent per brochure), then it is advisable to use the remaining 60 sheets to print fliers, so as to minimize costs.

Since 1 flier contains 2 pages,

with 60 sheets, the number of fliers that can be printed = 60/2 = 30 fliers

cost of 30 fliers = 30 × 6 cents = 180 cents

If the remaining 60 sheets are used to print brochures;

1 brochure has 3 pages,

therefore number of brochures to be printed = 60/3 = 20 brochures

cost of 20 brochures = 20 × 10 cents = 200 cents

This is why it is cheaper to print extra fliers at 180 cents.

Therefore total number of prints will be;

Brochures = 80

Fliers = 100 + 30 =130

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Answer:

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Step-by-step explanation:

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Assuming the thickness of the steel hex nut: t=2 cm

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V=Vp-Vc

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Volume of the cylinder: Vc


Prism:

Vp=Ab h

Ab=n L a / 2

Number of the sides: n=6

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Height of the prism: h=t=2 cm

Central angle in the hexagon: A=360°/n

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tan (A/2)=(L/2) / a

tan (60°/2)=(L/2) / (2 cm)

tan 30° = (L/2) / (2 cm)

sqrt(3)/3=(L/2) / (2 cm)

Solving for L/2:

(2 cm) sqrt(3)/3 = L/2

2 sqrt(3)/3 cm = L/2

Solving for L:

2 (2 sqrt(3)/3 cm)=L

4 sqrt(3)/3 cm = L

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Vp=16 (1.732) cm^3

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Cylinder:

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π=3.14

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Height of the cylinder: h=t=2 cm

Vc=[3.14 (1.6 cm)^2 / 4] (2 cm)

Vc=[3.14 (2.56 cm^2) / 4] (2 cm)

Vc=(2.0096 cm^2) (2 cm)

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V=27.712 cm^3 - 4.019 cm^3

V=23.693 cm^3

V=23.6 cm^3

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Answer: 1,468.5

Step-by-step explanation:

Hi, to answer this question we simply have to multiply the price of each share of stock ($19.58) by the number of shares of stock bought (75 ).

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His purchase price was 1,468.5

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2 years ago
If value of cos330° is √3/2 then find tan165°.
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Answer:

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Step-by-step explanation:

When cos(angle)=sqrt(3)/2

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Anyways 330 degrees is in the 4 quadrant.  Cosine is positive there while sine is negative.

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Therefore  tan(165)=tan(330/2)=(1-cos(330))/sin(330)=(1-sqrt(3)/2)/(-1/2)

Multiply top and bottom by 2 to get

tan(165)=(2-sqrt(3))/-1

tan(165)=-2+sqrt(3)

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