Answer:
Option 3 is right.
Step-by-step explanation:
Reference angle of x is obtained by either 180-x, 180+x. or 360-x depending on the posiiton of terminal whether II quadrant or iv quadrant, or iii quadrant, etc.
In whatever way we find reference angles,
cos will remain cos only and sin will remain sin only there may be only changes in sign.
Of all the ordered pairs given, we find that I, II, and Iv there is a switch over form cos to sine and sin to cos. Hence these options cannot be for reference angles.
III option is 
show that both sign and cos changed sign. This is possible only in III quadrant.
ie reference angle of orignal angle t = 180+t
SO this option is right.
Step-by-step explanation:
<u>Step 1: Convert into expressions</u>
y = one-fourth x minus 1 → 
y = negative one-half x minus one-fourth → 
They intersect at 
Answer: Option A, (1, negative three-fourths)
6. (5y+2)+14x=5y+(2+14x) (1point) A.associative property of addition B.associative property of multiplication C.commutative property of addition D.commutative property of multiplication 7. (m*n)*p=m*(n*p) (1 point) A. commutative property of addition B.commutative property of multiplication C.associative property of addition D. associative property of multiplication
Answer:
The age of Sue could be 7 years
Step-by-step explanation:
Jenny is 8 years older than twice her cousin Sue's age.
The first equation will be :
J = 8 + 2S ---------(1)
The sum of their ages is less than 32.
The second equation will be :
J + S < 32 ----------------(2)
Now rearrange both equations :
8 + 2S + S < 32
3S < 32 - 8
3S < 24
S < 24/3
S < 8
S = 7
The age of Sue could be 7 years.
X^3-7x^2-5x+35
= x^2(x-7) - 5 (x-7) now by definition
=(x^2-5)(x-7)
hope this helps
