Answer:
Options A,C and E.
Step-by-step explanation:
The given equation is
Let n be the unknown number, then
Twice a number minus nine and two-tenths is the same as the number plus four-fifths.
So, option A is correct.
Nine point two decreased by double a number is the same as the number added to four-fifths.
Nine point two less than twice a number is equal to the number added to four-fifths.
So, option C is correct.
Two times the difference of a number and nine and two-tenths is equal to the number plus four-fifths.
Double a number decreased by nine and two-tenths is the same as the sum of four-fifths and the number.
So, option E is correct.
Therefore, the correct options are A,C and E.
Answer:
9/81=1/9 The fraction 1/9 is a rational number. All rational numbers can be written as a fraction showing the relationship between two integers.
Step-by-step explanation:
Answer:
C. 3.8 min < ?X - ?Y < 4.8 min
Step-by-step explanation:
Let both flares be X and Y
For X
n1 = 35
Bar x1 =19.4
D1 = 1.4
For Y
n2 = 40
Bar X2= 15.1
S2 = 0.8
√(x1²/n1) + (x2²/n2)
=√ (1.4²/35)+(0.8²+40)
= 0.2683
Critical value, t = 2.032
We now have to calculate margin of error
0.2683x2.032
= 0.545 this is approximately equal to 0.5
Bar x1 - bar X2
= 19.4 - 15.1
= 4.3
At 95% confidence level
4.3+-0.5
4.3+0.5= 4.8
4.3-0.5 = 3.8
Therefore the answer is 3.8min<X-Y<4.8min
Let's assign some random values to it, and say 1 unit of petroleum costs 100 bitcoins, because we all know bitcoins are the best currency :P
If the price goes up by 10%, it is now 100*1.1 = 110bitcoins for 1 unit.
However he's only getting 0.9 units now, so multiplying 110 by 0.9 gives us 99 bitcoins. His petroleum bill used to be 100 (which is why I picked 100 as it's easier), and now it is 99. Therefore his petroleum bill has reduced by 1%
Answer:

Step-by-step explanation:
Given the inequality: 
Step 1: Distribute the bracket

Step 2: Subtract 10 from both sides

Step 3: Divide both sides by -2
Note that when you divide an inequality by a negative sign, the inequality sign is reversed.
