2 years ago

ANSWER ASAP Which statements about the values of 4.099 and 40.99 are true? Select all that apply.

Mathematics

1 answer:

Dmitriy789 [7]2 years ago

6 0

Answer:

the answer is C because is 10 times more

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Brody is purchasing some tools for his workshop. He has a budget of $120 and needs to buy at least 14 tools. Each hammer costs $

STatiana [176]

Answer:

For this case, the first thing we must do is define variables:

x: number of hammers

y: number of wrenches

We write the system of inequations:

10x + 6y <= 120

x + y> = 14

Step-by-step explanation:

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1 year ago

Fred buys a video game disk for $4 there was a discount of 20% what is the sales price please show work

polet [3.4K]

multiply the price by the discount then subtract the answer from the price

4 * 0.20 = 0.80

4-0.80 = 3.20

sale price is $3.20

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2 years ago

Little Mexican restaurant sells only two kinds of beef burritos: Mucho beef and Mucho Mucho beef. Last week in the restaurant so

Romashka [77]

Step-by-step explanation:

16+22=38

So then youll check out the price thats worth each. 231$ So what is 38 divided by 231$? Thats your answer

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2 years ago

Eli invested $ 330 $330 in an account in the year 1999, and the value has been growing exponentially at a constant rate. The val

Cloud [144]

Answer:

The value of the account in the year 2009 will be $682.

Step-by-step explanation:

The acount's balance, in t years after 1999, can be modeled by the following equation.

$A(t) = Pe^{rt}$

In which A(t) is the amount after t years, P is the initial money deposited, and r is the rate of interest.

$330 in an account in the year 1999

This means that $P = 330$

$590 in the year 2007

2007 is 8 years after 1999, so P(8) = 590.

We use this to find r.

$A(t) = Pe^{rt}$

$590 = 330e^{8r}$

$e^{8r} = \frac{590}{330}$

$e^{8r} = 1.79$

Applying ln to both sides:

$\ln{e^{8r}} = \ln{1.79}$

$8r = \ln{1.79}$

$r = \frac{\ln{1.79}}{8}$

$r = 0.0726$

Determine the value of the account, to the nearest dollar, in the year 2009.

2009 is 10 years after 1999, so this is A(10).

$A(t) = 330e^{0.0726t}$

$A(10) = 330e^{0.0726*10} = 682$

The value of the account in the year 2009 will be $682.

4 0

2 years ago

Let mAngleA = 40°. If AngleB is a complement of AngleA, and AngleC is a supplement of AngleB, find these measures. mAngleB = ° m

kati45 [8]

Answer:

B is 50° and C is 130°

Step-by-step explanation:

complementary angle

x+x=90°

40°+x=90°

x=90°-40°

x=50°

supplementary angles

x+x=180

50+x=180

x=180-50

x=30°

6 0

1 year ago

Read 2 more answers