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Vikentia [17]
2 years ago
10

Graph a line with a slope of -2/5 that contains the point (-3,5)

Mathematics
1 answer:
kotykmax [81]2 years ago
4 0

y=-\frac{2}{5}x+\frac{19}{5}

Further explanation:

We have to find the equation of the line first to graph the line.

The general form of slope-intercept form of equation of line is:

y=mx+b

Given

m=-\frac{2}{5}

Putting the value of slope in the equation

y=-\frac{2}{5}x+b

To find the value of b, putting the point (-3,5) in equation

5=-\frac{2}{5}(-3)+b\\5=\frac{6}{5}+b\\5-\frac{6}{5}+b\\b=\frac{25-6}{5}\\b=\frac{19}{5}

Putting the values of b and m

y=-\frac{2}{5}x+\frac{19}{5}

The graph is made by using online graphing tool Desmos.

Keywords: Equation of line, graph of line

Learn more about graphs at:

  • brainly.com/question/1557905
  • brainly.com/question/1554024

#LearnwithBrainly

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A small town's phone numbers either begin 373 or 377. How many phone numbers are available?
ser-zykov [4K]

Answer:

  • <u><em>There are 20,000 number available.</em></u>

Explanation:

To determine <em>how many phone numbers are available </em>you need to know how many digits the number contains.

I will assume the same number of digits for other similar questions, i.e. 7.

With 7 digits, the numbers that begin with 373 or 377 can be of the form 373XXXX or 377XXXX.

Where each X can be any digit 0 - 9. Then, there are 10 different options for each X.

Thus, there are 10×10×10×10 = 10,000 different numbers starting with 373 and other 10,000 different numbers starting with 377.

In total, there are 20,000 numbers available.

6 0
1 year ago
Copy and complete each table.
LUCKY_DIMON [66]

Answer:

5th term of sequence = -18

nth term of the sequence = -5n + 7

Step-by-step explanation:

Difference between successive and previous term of the output,

T_{2}-T_{1} = -3 - 2

           = -5

Similarly, T_{3}-T_{2}=-8-(-3)

                            = -5

There is a common difference 'd' = (-5)

Therefore, the sequence formed will be an arithmetic sequence.

First term of the sequence 'a' = 2

Explicit formula of an arithmetic sequence, T_{n} = a + (n - 1)d  [n = input value]

T_{n} = 2 + (n - 1)(-5)

    = 2 - 5n + 5

    = -5n + 7

5th term of this sequence,

T_{5}=2+(5-1)(-5)

    = 2 - 20

    = -18

Therefore, 5th term of sequence = -18

                  nth term of the sequence = -5n + 7

3 0
1 year ago
Katya cut part of the jump rope off to make it shorter. The new length is 8 and StartFraction 1 over 6 EndFraction feet. The dif
maksim [4K]

Answer:

9 feet it is right

Step-by-step explanation:

6 0
1 year ago
Read 2 more answers
The function y=7500(1.08)t represents the value y of an investment after t years. What is the value of the investment after 6 ye
boyakko [2]

Answer:

The answer is 48600, but I'm not entirely sure if it correct.

From what I know, if I were to see ¨y=7500(1.08)t¨, we could have to substitute the t with the number of years. Looking like this, ¨y=7500(1.08) x 6¨.

The reason I don know if my answer is correct or not since I don know if you have the t next to 1.08 to represent that or to simply multiply the property of it with 6 (the number of years).

So I tried...

Step-by-step explanation:


4 0
1 year ago
The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time
cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

1\leq t\geq \sqrt{2}

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

h =20-5t^{2}-----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height h = 15m  

Put height value in equation 1

15 =20-5t^{2}

5t^{2} =20-15

5t^{2} =5

t^{2} =1

t =\pm1

We know that the time is always positive, therefore t=1

when the stuntman is 10m above the ground.

height h = 10m  

Put height value in equation 1

10 =20-5t^{2}

5t^{2} =20-10

5t^{2} =10

t^{2} =\frac{10}{5}

t^{2} =2

t=\pm\sqrt{2}

t=\sqrt{2}

Therefore ,time interval of camera film him is 1\leq t\geq \sqrt{2}

7 0
2 years ago
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