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spayn [35]
2 years ago
6

Kenise is looking for a job that has benefits. She'd like to work in one place and not have to search for a new job anytime soon

.
Kenise is looking for a
(Full-time, half time, part time) job. She would most likely be paid(a salary, an hourly wage, by the project)
Mathematics
2 answers:
solong [7]2 years ago
5 0

Answer:

Kenise is looking for a job that has benefits. She'd like to work in one place and not have to search for a new job anytime soon. Kenise is looking for a Full-time job. She would most likely be paid an hourly wage, by the project.

Nimfa-mama [501]2 years ago
5 0

Answer:

Step-by-step explanation:

i *think* it's hourly wage ,but correct me if i'm wrong

You might be interested in
The smallest number by which 28 should be multiplied so as to get a perfect square is​
dsp73

Answer:

7.

Step-by-step explanation:

28 = 2^2 * 7.

To multiply 28 to get a perfect square, we can multiply it by 7 to get 2^2 * 7^2, which is 14 squared.

4 0
2 years ago
Tim has an after-school delivery service that he provides for several small retailers in town. He uses his bicycle and charges $
nlexa [21]

Answer:

<em>$4.84</em>

<em></em>

Step-by-step explanation:

Given that

For delivery within 1\frac{1}2 mi, charges = $1.25

For delivery within 1\frac{1}2 mi - 1\frac{3}4 mi, charges = $1.70

For delivery within 1\frac{3}4 mi - 2 mi, charges = $2.15

and

so on.

i.e.

For delivery within 2 mi - 2\frac{1}4 mi, charges = $2.60

For delivery within 2\frac{1}4 mi - 2\frac{1}2 mi, charges = $3.05

For delivery within 2\frac{1}2 mi - 2\frac{3}4 mi, charges = $3.50

For delivery within 2\frac{3}4 mi - 3 mi, charges = $3.95

For delivery within 3 mi - 3\frac{1}4 mi, charges = $4.40

So, every 0.25 mi or \frac{1}4 mi increase in distance, there is an increase of $0.45 in the charges.

It is given that there is increase of 10% in the rates.

i.e. for every 0.25 mi increase in distance, there is an increase of 0.45*1.10 = $0.495 in the charges.

The distance of 3\frac{1}8 miles lies within the range 3 mi - 3\frac{1}4 mi.

So actual charges after increase of 10%

\Rightarrow \$4.40 \times \dfrac{110}{100}\\\Rightarrow \$4.40 \times 1.10\\\Rightarrow \bold{\$4.84}

6 0
2 years ago
they paid $13 for each pepperoni pizza and $11for each plain pizza the club bought total of 18 pizzas for the party and paint a
jeka94

Complete question;

A booster club paid for pizzas for an  end of season party. They paid $13  for each pepperoni pizza and $11 for  each plain pizza. The club bought a

total of 18 pizzas for the party and  paid a total of $212.

Drag and drop the numbers to the  boxes to create an equation which  models this situation if x = the  number of pepperoni pizzas and y =  the number of plain pizzas bought.

Answer:

13x + 11y = 212

Step-by-step explanation:

They bought 2 different recipe of pizza. The first is the pepperoni pizza and the second kind is the plain pizza. The pepperoni pizza cost $13 each while the  plain Pizza cost $11 each. The total number of pizza bought is 18 in number.

The total cost of the pizza is also $212.

number of pizza bought = 18

total cost of pizza = $212

x = the  number of pepperoni pizzas

y =  the number of plain pizzas

The number of pepperoni pizzas multiply by the cost for each will give the cost of the pepperoni pizzas. This same method is applied to get the cost of the plain pizzas.

Therefore, adding the individual cost of the kinds of pizza will give the total cost of the pizzas.

13x + 11y = 212

4 0
2 years ago
Madison starts with a population of 1,000 amoebas that triples in size every hour for a number of hours, h. She writes the expre
gtnhenbr [62]

Answer: The meaning of each term of the  Madison’s and Tyler’s expressions is mentioned below.

Step-by-step explanation:

Since, when Madison starts with a population of 1,000 amoebas that triples in size every hour for a number of hours, h.

That is, after 1 hour total number of amoebas = 3×1000 = 3^1\times 1000

After 2 hour,  total number of amoebas = 3×3000=3^2\times 100

After 3 hour, total number of amoebas = 3×9000= 3^3\times 1000

similarly, after h hours, total number of amoebas,

f(h) = 3^h\times 1000

where, 1000 is the initial population of amoeba 3 is the growth factor of population and f(h) is the population of amoeba after h hours.

Since, when Tyler starts with a population of 1 amoeba that  increases 30% in size every hour for a number of hours.

That is, after 1 hour total number of amoebas = (1+0.3)^1

After 2 hour,  total number of amoebas =  (1+0.3)^2

After 3 hour, total number of amoebas =  (1+0.3)^3

Similarly, after h hours, total number of amoebas,

f(h) =(1+0.3)^h

Where,  1 is the initial population of amoeba, 0.3 is the growth rate and 1.3 is the growth factor.


5 0
2 years ago
Read 2 more answers
9x-2y=11 <br> 5x-2y=15 <br> what is the solution to the above system of equations<br> ASAP
natali 33 [55]

9x - 2y = 11 ... (i)

5x - 2y = 15 ... (ii)

Subtracting equation (ii) from (i) we get;

4x + 0 = -4

4x=-4 , x = -1

Replacing x = -1 in equation (i) we get;

9(-1) - 2y = 11

-9 - 2y = 11

-2y = 20

y = 20 ÷ -2 = -10

The solution to the system of equations is (-1,-10).

8 0
2 years ago
Read 2 more answers
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