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2 years ago

610 people go on a coach trip each coach can hold 55 people how many coaches are needed

Mathematics

2 answers:

jeka942 years ago

8 0

Answer:

Step-by-step explanation:

610 divided by 55

diamong [38]2 years ago

4 0

Answer:

Step-by-step explanation:

610 divided by 55 = 11.09

but since u cant have 11.09, u need 12

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A class in advanced physics is composed of 10 juniors, 30 seniors, and 10 graduate students. the final grades show that 3 of the

const2013 [10]

Solution: We are given:

Total students = 10 + 30 + 10 =50

Number of students who received A grade = 3 + 10 + 5 = 18

Number of senior student's who received A grade is = 10

Let A be the event that the student is senior and B be the event that he or she earned an A. Then,

$P(A \cap B)=\frac{10}{50}$

$P(B) = \frac{18}{50}$

Now the probability a student chosen at random from this class and is found to have earned an A, the probability that he or she is a senior is:

$P(A|B) = \frac{P(A \cap B}{P(B)}$

$=\frac{\frac{10}{50} }{\frac{18}{50} }$

$=\frac{10}{18}=\frac{5}{9} =0.556$

5 0

2 years ago

Every day, a lecture may be canceled due to inclement weather with probability 0.05. Class cancelations on different days are in

andrezito [222]

<h3>(a)Probability of cancelling at least 4 classes is 0.0055.</h3><h3>(b)Probability of 10th class is third class that gets cancelled = 0.0031</h3>

Step-by-step explanation:

Here, the question is<u> incomplete</u>.

Every day, a lecture may be canceled due to inclement weather with probability 0.05. Class cancellations on different days are independent.

(a) There are 15 classes left this semester. Compute the probability that at least 4 of them get canceled.

(b) Compute the probability that the tenth class this semester is the third class that gets canceled.

Now, here:

The probability of cancelling each class = 0.05

Now, probability of cancelling at least 4 classes

= 1 - P(Cancelling at max 3 classes)

= 1 - P(0 ≤ x ≤ 3) = 1 - Binomial (15,0.05,3)

= 0.0055

Hence, probability of cancelling at least 4 classes is 0.0055.

(b) As given, 10th class is third class that gets cancelled.

So, the first and second classes that get cancelled in between 1 - 9.

P(2 class cancelled in 1st 9) = Binomial (15,0.05,3) = 0.0629

Also, as given P(10th class cancelled) = 0.05

⇒ P(10th class is third class that gets cancelled ) = 0.0629 x 0.05 = 0.0031

5 0

1 year ago

Find the product. (a2)(2a3)(a2 – 8a + 9) 2a7 – 16a6 + 18a5 2a7 – 16a6 – 18a5 2a8 – 16a7 + 18a6 2a12 – 16a7 + 18a6 consider the d

Fofino [41]

Answer: $2x^7 -16a^6 +18a^5$

Step-by-step explanation: Given expression $(a^2)(2a^3)(a^2-8a + 9)$ .

The first factor $(a^2)$ has a degree of : 2 because power of a is 2.

The second factor $(2a^3)$ has a degree of : 3 because power of a is 3.

The third factor $(a^2-8a + 9)$ has a degree of : 2 because highest power of a is 2.

Let us multiply them now:

$(a^2)(2a^3)(a^2-8a + 9).$

First we would multiply $(a^2)(2a^3)$ .

According to product rule of exponents, we would add the powers of a.

Therefore,

$(a^2)(2a^3) = 2a^{2+3}= 2a^5$

Now, we need to distribute $2a^5$ over $(a^2-8a + 9)$

Therefore,

$(2a^5)(a^2-8a + 9)= 2a^{5+2} -16a^{5+1}+18a^5$

= $2x^7 -16a^6 +18a^5$

Highest power of resulting polynomial $2x^7 -16a^6 +18a^5$ is 7.

Therefore, The product has a degree of 7.

5 0

1 year ago

Read 2 more answers

Which of the following functions describes the sequence 4, –2, 1, –12, 14, . . .? A. f(1) = 4, f(n + 1) = –2f(n) for n ≥ 1 B. f(

AlekseyPX

Answer: D. $f(1) = 4,\ \ f(n+1)=\dfrac{-1}{2}f(n)$

Step-by-step explanation:

The given sequence: $4, -2,1,\dfrac{-1}{2},\dfrac14,....$

Here, first term: $f(1)=4$

Second term: $f(2)=-2$

Third term : $f(3)=\dfrac{-1}{2}$

It can be observed that it is neither increasing nor decreasing sequence but having the common ratio.

Common ratio: $r=\dfrac{f(2)}{f(1)}=\dfrac{-2}{4}=\dfrac{-1}{2}$

So, $f(n+1)=\dfrac{-1}{2}f(n)$ [as in G.P. nth term= $a_{n+1}=ar^n$ ]

Hence, correct option is D. $f(1) = 4,\ \ f(n+1)=\dfrac{-1}{2}f(n)$

5 0

1 year ago

The number of hours walked varies inversely with the speed of the walker. if it takes sam 12 hours to complete his walking goal

Effectus [21]

We let k be the proportionality constant for the relationship between number of hours, h and speed of the walker, s.

h = k/s
Substituting the known values,
12 = k/5
k = 60

For the second scenario,
h = k/s
Substituting the calculated value for k and the given value for speed,
h = (60)(3 miles/hour)
h = 20 hours
h = 20 hours

Therefore, it will take 20 hours to walk with a speed of 3 miles per hour.

7 0

1 year ago