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Nastasia [14]
1 year ago
11

math help ! Will give branliest !! At a car and truck dealership, the probability that a vehicle is white is 0.25 . The probabil

ity that it is a pick up truck is 0.15 . The or obability that it is a white pick up truck is 0.06 . What is the probability that the vehicle is white, given that the vehicle is a pickup truck . Round your answer to two decimal places .
Mathematics
1 answer:
defon1 year ago
7 0

Answer:

As per the statement:

Let  Event A represents the probability that a vehicle is white and Event B  represents the probability that it is a pick up truck .

then;

P(A) = 0.25 and P(B) = 0.15

It is also given that:

The Probability that it is a white pick up truck is 0.06.

⇒P(A \cap B) = 0.06 where A \cap B represents that it is white pick up truck.

We have to find the the probability that the vehicle is white {given that the vehicle is a pickup truck}

We use the formula:

P(A/B) = \frac{P(A \cap B)}{P(B)}

where

A/B represents that the pick up truck vehicle is white.

Substitute the given values we get;

P(A/B) = \frac{0.06}{0.15} = 0.4

Therefore,  the probability that the vehicle is white, given that the vehicle is a pickup truck is 0.4

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Jenna’s method: Mia’s method:
boyakko [2]

Answer:

Mia's method have one advantage that the steps became less than Jenna's method.          

Step-by-step explanation:

Jenna’s method :

5(30 + 4)

=(5)(30) + (5)(4)

=150 + 20

=170

Mia’s method :

5(30 + 4)

=(5)(34)

=170

To find : Explain why both Jenna and Mia arrived at the same answer and the advantage of one method over the other ?

Solution :

The method of both were different but correct.

One apply distributive property and other apply direct calculation.

So, both Jenna and Mia arrived at the same answer

But Mia's method have one advantage that the steps became less than Jenna's method.

5 0
2 years ago
Read 2 more answers
At East Middle School, there are 58 left-handed students and 609 right-handed students. The numbers of left- and right-handed st
EastWind [94]

<u>Answer:</u>

C. Left-handed: 48, Right-handed: 504

D. Left-handed: 30, Right-handed: 315

<u>Step-by-step explanation:</u>

We are given that there are 58 left-handed students and 609 right-handed students at East Middle School and these numbers of students are proportional to the number of left and right handed students at East Middle School.

Given the above information, we are are to determine which two options could be the the numbers of left-handed and right-handed students at West Junior High.

Ratio of right handed to left handed students at East Middle School = \frac{609}{58} = 10.5

Checking for ratios of the given options:

A. \frac{483}{42} =11.5

B. \frac{378}{28} =13.5

C. \frac{504}{48} =10.5

D. \frac{560}{56} =10

E. \frac{315}{30} =10.5

Therefore, the possible numbers of left-handed and right-handed students at West Junior High could be C. Left-handed: 48, Right-handed: 504 and D. Left-handed: 30, Right-handed: 315.

7 0
1 year ago
Read 2 more answers
If f(x)=x2+10sinx, show that there is a number c such that f(c)=1000.
gayaneshka [121]
F(x) is continuous for all x.

Pick a point and show that f(x) is either negative or positive. Pick another point and show that f(x) is negative, if positive, or positive, if negative.

At x = 30, f(30) - 1000 = 900 + 10sin(30) - 1000 ≤ 0
Now, show at another point f(x) - 1000 is positive, and hence, there would be root between 30 and such point.

Let's pick 40.
At x = 40, f(40) - 1000 = 1600 + 10sin(40) - 1000 ≥ 0

Since f(x) - 1000 is continuous, there lies a root between 30 and 40, and hence, 30 ≤ c ≤ 40
7 0
2 years ago
If c = 10d, what percent of 3c is 3d?
son4ous [18]

Answer:

1000%

Step-by-step explanation:

c=10d,

3c will become 3*10d=30d

d is 10 times to c which converts to 1000%

6 0
1 year ago
To increase sales, a local donut shop began putting an extra donut in some of the boxes. Customers are unaware of which boxes ha
Bingel [31]

Answer:

Step-by-step explanation:

Hello!

Part A

First, determine your study variable:

X: Number of boxes with an extra donut in a sample of eight.

To see if the variable has a Binomial distribution you have to check if the binomial criteria are met:

1. The number of observation of the trial is fixed (In this case n = 8, the boxes each customer bought make the sample)

2. Each observation in the trial is independent, this means that none of the trials will affect the probability of the next trial (In this case, the amount of donuts in one box does not affect on the probability of the next box having an extra donut)

3. The probability of success in the same from one trial to another (In this case our "success" will be that the box has an extra donut, according to the owners claim that is 1/7; ρ=0,14)

So X≈ Bi (n;ρ)

Where n represents the sample (n=8) and ρ is the probability of success (ρ=0.14)

Part B

The mean of the binomial distribution is E(X)= nρ

E(X)= 8 * 0.14= 1.12

The mean of the distribution is also called the expected value. You'd expect that 1.12 boxes have an extra donut.

The variance of the binomial distribution is V(X)= nρ(1 - ρ)

V(X)= 8*0.14*(1 - 0.14)= 0.9632

Its square root is the standard deviation

√V(X)= 0.98

The standard deviation is a measure of dispersion, it indicates how much the values ​​of the distribution of the central value are separated. In this case, 0.98 indicates that the distribution of the number of boxes with an extra donut is far from the expected value.

Part C

Two of the eight customers buy a box with an extra donut, symbolically:

P(X=2) = P(X≤2) - P(X≤1)= 0.91 - 0.68 = 0.22

There is a 22% chance that two customers bought a box with an extra donut.

Compute:

P(X≥2)= 1 - P(X<2)= 1 - P(X≤1)= 1 - 0.68= 0.32

There is a 32% chance that two or more customers bought a box with an extra donnut.

I hope it helps!

3 0
1 year ago
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