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Margaret [11]
1 year ago
9

If c = 10d, what percent of 3c is 3d?

Mathematics
1 answer:
son4ous [18]1 year ago
6 0

Answer:

1000%

Step-by-step explanation:

c=10d,

3c will become 3*10d=30d

d is 10 times to c which converts to 1000%

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in the diagram below, <AFB = <EFD. if m<EFD = (5x+6)°, m<DFC = (19x-15)°, and m<EFC = (17x+19)°, find m<AFE​
NeX [460]

Answer:

m<AFE​ =  128°.

Step-by-step explanation:

<u>Step 1: Find the value of x</u>

<em>Angle EFD + Angle DFC = Angle EFC</em>

5x + 6 + 19x - 15 = 17x + 19

24x - 9 = 17x + 19

7x = 28

x = 4

<u>Step 2: Find all angles</u>

<em>Angle AFB=Angle EFD= 5x + 6</em>

5(4) + 6 = 26°

Angle DFC = 19x - 15

19(4) - 15 = 61°

<u>Step 3: Find angle AFE</u>

<em>Line BD is a straight line and all angles on a straight line are equal to 180°.</em>

<em>Angle AFB + Angle AFE + Angle EFD = 180°</em>

26 + BFC + 26 = 180°

BFC = 180 - 52

BFC = 128°

<em>Therefore, m<AFE​ is equal to 128°.</em>

!!

3 0
1 year ago
Rachel has completed 2/3 of her shift; Jose has completed 1/6 of his shift; Damon has finished 4/5 of his shift; and Stacy has 6
Alisiya [41]

Answer:

C. Stacy

Step-by-step explanation:

One way to compare is to convert all the fractions into decimals

    Rachel works 2/3 of her shift: Approximately= 0.667

    Jose works 1/6: approx. = 0.1667

    Damon works 4/5= 0.80

    Stacy works 6/7: approx. = 0.8571

Now this makes it much easier to compare

And since 0.85714 (Stacy's shift) is the largest number, Stacy has completed the largest portion of her shift

4 0
1 year ago
If terri were stretching 4 days per week, how many days per week would she need to stretch to increase her frequency variable? 1
Olin [163]

Answer:

3 days is the right answer!!!!! good luck

Step-by-step explanation:


4 0
1 year ago
Read 2 more answers
23) An extension ladder forming a 60° angle with the ground is placed against
Pachacha [2.7K]

Answer: the length of the extended ladder is 8√3 feet or 13.9 feet

the distance between the wall and the bottom of the ladder is 4√3 feet or 6.9 feet

Step-by-step explanation:

The ladder forms a right angle triangle with the building and the ground. The length of the ladder represents the hypotenuse of the right angle triangle. The height from the top of the ladder to the base of the building represents the opposite side of the right angle triangle.

The distance from the bottom of the ladder to the base of the building represents the adjacent side of the right angle triangle.

To determine the extended length of the ladder h, we would apply

the Sine trigonometric ratio.

Sin θ = opposite side/hypotenuse. Therefore,

Sin 60 = 12/h

√3/2 = 12/h

h = 12 × 2/√3 = 24√3

h = 24√3 × √3/√3

h = 8√3

To determine the distance between the wall and the bottom of the ladder d, we would apply

the cosine trigonometric ratio.

Cos θ = adjacent side/hypotenuse.

Therefore,

Cos 60 = d/8√3

0.5 = d/8√3

d = 0.5 × 8√3

d = 4√3

3 0
1 year ago
The United States Bureau of Labor Statistics (BLS) conducts the Quarterly Census of Employment and Wages (QCEW) and reports a va
Firlakuza [10]

Answer:

1

  The  probability is  P(\= X < 33) = 0.8531

2

  The  probability is  P(\= X > 30) = 0.3520

Step-by-step explanation:

From the  question we are told that

     The population mean is  \mu =  28.29

      The standard deviation is \sigma  =  33.493

       The sample size is  n  = 56

Generally the standard error for the  sample  mean (\= x ) is mathematically evaluated as

        \sigma _{\=x} =  \frac{\sigma}{\sqrt{n} }

substituting values  

       \sigma _{\=x} =  \frac{33.493}{\sqrt{56} }

      \sigma _{\=x} = 4.48

Apply central limit theorem[CLT] we have  that

        P(\= X < 33) =  [z <  \frac{33 -  \mu }{\sigma_{\= x}} ]

substituting values

       P(\= X < 33) =  [z <  \frac{33 -  28.29 }{4.48} ]

       P(\= X < 33) =  [z <  1.05 ]

From the z-table  we have that  

       P(\= X < 33) = 0.8531

For the second question

    Apply central limit theorem[CLT] we have  that

    P(\= X > 30 ) =  [z >  \frac{30 -  \mu }{\sigma_{\= x}} ]

substituting values

   P(\= X < 33) =  [z >  \frac{30 -  28.29 }{4.48} ]

From the z-table  we have that  

     P(\= X < 30) = 0.6480

Thus  

     P(\= X > 30) = 1- P(\= X < 30) = 1- 0.6480

     P(\= X > 30) = 0.3520

3 0
2 years ago
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