If x = 45, y = 63, and the measure of AC = 4 units, what is the difference in length between segments AB and AD? Round your answ
er to the nearest hundredth. triangles ABC and ADC in which angle C is a right angle, point D is on segment BC between points B and C, the measure of angle ABD is x degrees, and the measure of angle ADC is y degrees 0.74 units 1.17 units 1.64 units 2.14 units
1 answer:
Answer:
1.17 units
Step-by-step explanation:
Given :
If x = 45, y = 63, and the measure of AC = 4 units, what is the difference in length between segments AB and AD?
x= 45° ; y = 63° AC = 4 units
From trigonometry,
Taking triangle ADC;
sinθ = opposite / Hypotenus
Sin63° = 4 / AD
AD = 4 / 0.891 = 4.489 units
From triangle ABC;
sin45° = 4 / AB
AB = 4 / 0.7071
AB = 5.656 units
Difference = (5.657 - 4.489) units
= 1.167 units
= 1.17 units (nearest hundredth)
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Answer:
Option A -
Step-by-step explanation:
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To find : Identify the values of following?
Solution :
The nth term of the sequence is
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When n=2,
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So, Option A is correct.
Answer:
a) 0.997 is the probability that the breaking strength is at least 772 newtons.
b) 0.974 is the probability that this material has a breaking strength of at least 772 but not more than 820
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 800 newtons
Standard Deviation, σ = 10 newtons
We are given that the distribution of breaking strength is a bell shaped distribution that is a normal distribution.
Formula:
a) P( breaking strength of at least 772 newtons)
Calculation the value from standard normal z table, we have,
0.997 is the probability that the breaking strength is at least 772 newtons.
b) P( breaking strength of at least 772 but not more than 820)
0.974 is the probability that this material has a breaking strength of at least 772 but not more than 820.