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2 years ago

6

The experimental probability that Kevin will catch a fly ball is equal to 7/8. About what percent of the time will Kevin catch a

fly ball?

1 answer:

Paladinen [302]2 years ago

6 0

Answer:

87.5% percent chance.

Trust me it's right.

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Given the median 24 and trapezoid MNOP what is the value of x

masha68 [24]

1. Given the bases a and b of a trapezoid, the length of the median m can be found by the formula $m= \frac{a+b}{2}$

2. MP and NO are the bases so applying the above formula:

$24= \frac{(x+8)+(5x+4)}{2}$

$48= 6x+12$

$6x=36$

x=6

Check the picture for the proof of the theorem m=(a+b)/2

8 0

2 years ago

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Simplify the radical expression

LenKa [72]

<span>To multiply two radicals together, we can simply multiply both the values inside the radicals together and put that in a radical.
So for 5*sqrt(45b) * 6*sqrt(48b), we get 30*sqrt(45b*48b) = 30*sqrt(2160b^2). This value can be simplified further by taking out b^2 and 12^2 from the radical giving us the answer 360b*sqrt(15).</span>

3 0

2 years ago

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Bill is bisecting an angle with technology. Which of the following describes his next step?

mojhsa [17]

Answer:

the first step is correct

Step-by-step explanation:

the first step is correct

then draw 2 circles with the same radius with centre D and E ( the point BC intersect the first circle )

Where the 2 circles are intersecting is the point F

Then BF is the bisector

7 0

2 years ago

Consider a single spin of the spinner.

alex41 [277]

Answer:

"landing on a shaded portion and landing on a 3"

"landing on an unshaded portion and landing on a number less than 2 "

Step-by-step explanation:

Mutually exclusive means the events will have no intersection.

Let's look at your first choice:

"landing on a shaded portion and landing on an even number"

Landing on a shaded portion would be 1 or 4.

Landing on an even number would be 2 or 4.

There is an intersection (they contain a common element), the 4.

These events are not mutually exclusive.

Let's look at your second choice:

"landing on a shaded portion and landing on a number greater than 3"

Landing on a shaded portion would be 1 or 4.

Landing on a number greater than 3 would be just 4.

There is an intersection; they both contain 4.

These events are not mutually exclusive.

Let's look at your third choice:

"landing on a shaded portion and landing on a 3"

Landing on a shaded portion would be 1 or 4.

Landing on 3 would just be 3.

There is no common elements in the lists listed. These events have no intersection.

These events are mutually exclusive.

Let's look at your fourth choice:

"landing on an unshaded portion and landing on an odd number"

Landing on a unshaded portion would be 2 or 3.

Landing on an odd number would be 1 or 3.

There is an intersection; they both have 3 in common.

These events are not mutually exclusive.

Let's look at your fifth choice:

"landing on an unshaded portion and landing on a number less than 2 "

Landing on an unshaded portion would 2 or 3.

Landing on a number less than 2 would be 1.

There is no intersection.

These events are mutually exclusive.

6 0

2 years ago

Read 2 more answers

The gestation period of rhinos (487 days) is _____ percent longer than the gestation period of bears (220 days).

Talja [164]

Answer:

The gestation period of rhinos (487 days) is 121. 3 percent longer than the gestation period of bears (220 days).

Step-by-step explanation:

Given:

Gestation period of rhinos = 487 days

Gestation period of bears = 220 days

To Find:

Percentage increase = ?

Solution:

The percentage increase = $\frac{ \text{new value} - \text{final value} }{\text{final value}} \times 100$

On substituting the values,

= $\frac{ 487 - 220}{220}\times 100$

= $\frac{267}{220}\times 100$

=> $1.213 \times 100$

=> 121.3 %

8 0

2 years ago