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katovenus [111]

1 year ago

7

A bicycle tire has a radius of 26 inches. How many revolutions will this tire make if the bicycle is pedaled 1 mile? (Use 3.14 f

or π and 1 mile = 5280 feet).

1 answer:

Fittoniya [83]1 year ago

4 0

How far does a wheel move when it rotates once? The length of the outside of the tyre? Isn't that the same as the circumference?

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Grace rakes leaves everyday for one week. She fills the same number of bags with leaves on each of the 5 weekdays. She fills 11

svlad2 [7]

Answer:

3 bags per weekday

Step-by-step explanation:

Total bags of leaves at the end of the week = 26 bags

Bags of leaves she fills over the weekend = 11 bags

Bags of leaves she fills during weekdays = x bags

Total bags of leaves at the end of the week = Bags of leaves she fills over the weekend + Bags of leaves she fills during weekdays

26 = 11 + x

Subtract 11 from both sides

26 - 11 = 11 - 11 + x

15 = x

x = 15 bags

If she fills the same number of bags with leaves on each of the 5 weekdays.

how many bags she filled each weekday.

Bags she filled each weekday = Total Bags of leaves she fills during weekdays / 5 weekdays

= 15 bags / 5 weekdays

= 3 bags per weekday

7 0

2 years ago

Only 35% of the drivers in a particular city wear seat belts. Suppose that 20 drivers are stopped at random what is the probabil

lesya692 [45]

Here we have a situation where the probability of a driver wearing seat belts is known and remains constant throughout the experiment of stopping 20 drivers.

The drivers stopped are assumed to be random and independent.

These conditions are suitable for modelling using he binomial distribution, where

where n=number of drivers stopped (sample size = 20)

x=number of drivers wearing seatbelts (4)

p=probability that a driver wears seatbelts (0.35), and

C(n,x)=binomial coefficient of x objects chosen from n = n!/(x!(n-x)!)

So the probability of finding 4 drivers wearing seatbelts out of a sample of 20

P(4;20;0.35)

=C(20,4)*(0.35)^4*(0.65)^16

= 4845*0.0150061*0.0010153

= 0.07382

6 0

2 years ago

Determine the margin of error, m , of a 99% confidence interval for the mean IQ score of all students with the disorder. Assume

madreJ [45]

Answer:

E= 6.45

standard deviation is σ = 15,

The critical value is z(α/2) = 2.58.

Step-by-step explanation:

Margin error is the value that is lie above and below the sample.It gives percentage of numbers.Its is the product of critical value standard deviation and standard error of statistic.

General formula for the margin of error is

Margin of error = critical value × standard error of statistic

= $z \alpha /2$ × σ √n

z-value from two tailed is listed below:

From the table of standard normal distribution, probability value of 0.10.

row and column values gives the area to the two tail of z.

The positive z value is 2.58.

standard deviation is σ = 15,

The critical value is z(α/2) = 2.58.

after putting these vales we obtain the margin of error value that is

E= 6.45

7 0

2 years ago

In a West Texas school district the school year began on August 1 and lasted until May 31. On August 1 a Soft Drink company inst

WINSTONCH [101]

Answer:

$95.78

Step-by-step explanation:

f(t) = 300t / (2t² + 8)

t = 0 corresponds to the beginning of August. t = 1 corresponds to the end of August. t = 2 corresponds to the end of September. So on and so forth. So the second semester is from t = 5 to t = 10.

$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt

$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt

$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt

$T₂ = 75 ln(t² + 4) |₅¹⁰

$T₂ = 75 ln(104) − 75 ln(29)

$T₂ ≈ 95.78

3 0

2 years ago

The foodservice department has been asked to prepare a special luncheon for the grandway hospital board of directors on tuesday.

AURORKA [14]

125/21 = 150/x
cross multiply
125x = 3150
x = 3150/125
x = 25.2 lbs....rounded up = 26 lbs <==

5 0

2 years ago