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katovenus [111]

1 year ago

7

A bicycle tire has a radius of 26 inches. How many revolutions will this tire make if the bicycle is pedaled 1 mile? (Use 3.14 f

or π and 1 mile = 5280 feet).

1 answer:

Fittoniya [83]1 year ago

4 0

How far does a wheel move when it rotates once? The length of the outside of the tyre? Isn't that the same as the circumference?

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A 90 k g shopper is standing on an escalator that makes a 25 ∘ incline with the horizontal. The escalator carries the shopper to

Nitella [24]

Answer:

W= 27 k J

Step-by-step explanation:

Given that

mass ,m = 90 kg

Height , h= 30 m

angle , θ = 25°

The work done by escalator is given as follows

W = m g h

Work done by escalator does not depends on the angle ,it depends only on height.

Now by by putting the values in the above equation we get

W= 90 x 10 x 30 J ( take g = 10 m/s² )

W= 27000 J

W= 27 k J

Therefore work done by escalator will be 27 k J.

8 0

2 years ago

David can proofread15 reports in an hour while Armando can proofread 37reports in an hour. If they have 400 reports to proofread

ycow [4]

Together, it would take them 6 hours

8 0

2 years ago

Read 2 more answers

naveed makes 6.5litres of soup,correst to the nearest 0.5 litre he serves portions of his soup in 330ml cups correct to the near

Karolina [17]

Answer:

Number of Cups = 19

Step-by-step explanation:

Given

Size of Soup = 6.5 litres

SIze of cup = 330 ml

Required

Number of Cups.

First, it'll be assumed that the size of cups are uniform (the same).

The number of cups needed is calculated by dividing the size of soup by the size of the cup;

Number of Cup = Size of Soup/Size of Cup

Number of Cup = 6.5 litres/ 330 ml

<em>Convert units;</em>

<em>1 litres = 1000 ml</em>

<em>So,</em>

<em>6.5 litres = 6.5 * 1,000 ml</em>

<em>6.5 litres = 6,500 ml</em>

<em></em>

So,

Number of Cups = 6500 ml/330 ml

Number of Cups = 19.696969697

From the solution above, Naveed will definitely be able to serve 19 cups. The remaining fractional part won't fill a cup;

Hence, Number of Cups = 19

3 0

2 years ago

Andrew is buying pencils, and he wants to buy fewer than 25. He plans to give 75% of the pencils to his students and save three

sweet-ann [11.9K]

Answer:

50%

Step-by-step explanation:

the will have 75minis 25

4 0

2 years ago

Read 2 more answers

"Majesty Video Production Inc. wants the mean length of its advertisements to be 30 seconds. Assume the distribution of ad lengt

Westkost [7]

Answer:

a) $\bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})$

b) $Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5$

c) $P(\bar X >31.25)=0.006=0.6\%$

d) $P(\bar X >28.25)=0.9997=99.97\%$

e) $P(28.25$

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variabl length of advertisements produced by Majesty Video Production Inc. We know from the problem that the distribution for the random variable X is given by:

$X\sim N(\mu =30,\sigma =2)$

We take a sample of n=16 . That represent the sample size.

a. What can we say about the shape of the distribution of the sample mean time?

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is also normal and is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})$

b. What is the standard error of the mean time?

The standard error is given by this formula:

$Se=\frac{\sigma}{\sqrt{n}}=\frac{2}{\sqrt{16}}=0.5$

c. What percent of the sample means will be greater than 31.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

$z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}$

And we want to find this probability:

$P(\bar X >31.25)=1-P(\bar X$

d. What percent of the sample means will be greater than 28.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula is given by:

$z=\frac{\bar X- \mu}{\frac{\sigma}{\sqrt{n}}}$

And we want to find this probability:

$P(\bar X >28.25)=1-P(\bar X$

e. What percent of the sample means will be greater than 28.25 but less than 31.25 seconds?"

We want this probability:

$P(28.25$

3 0

2 years ago