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OLEGan [10]
1 year ago
11

Which is a characteristic of the line that passes through the points (6, 10) and (12, 7)? The slope is mc015-1.jpg. The slope is

mc015-2.jpg. The y-intercept is 7. The y-intercept is 13.
Mathematics
2 answers:
bonufazy [111]1 year ago
10 0

Answer:

D. The y-intercept is 13.

Step-by-step explanation:

lbvjy [14]1 year ago
8 0
Answer:
slope of the line is -0.5
y-intercept is 13

Explanation:
The general formula of the linear equation is:
y = mx + c 
where m is the slope and c is the y-intercept

1- getting the slope:
We are given the two points:
(6,10) representing (x1 , y1)
(12,7) representing (x2 , y2)
The slope of the line will be calculated as follows:
m = (y2-y1) / (x2-x1) = (7-10) / (12-6) = -3/6 = -0.5
The equation of the line now becomes:
y = -0.5x + c

2- getting the value of the y-intercept:
To get the value of the y-intercept (c), we will use any of the given points, substitute in the equation of the line and solve for c. I will use the point (6,10) as follows:
y = -0.5x + c
10 = -0.5(6) + c
10 = -3 + c
c = 13

Based on the above, the equation of the line would be:
y = -0.5x + 13

Hope this helps :)
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If EBC = 31a - 2 and EBH = 4a + 45 find HBC
Zigmanuir [339]

Answer:

The measure of angle HBC is m∠HBC=61°

Step-by-step explanation:

In this problem we have that

The line BH bisects angle EBC,

see the attached figure to better understand the problem

then

m∠EBC=m∠EBH+m∠HBC

m∠EBH=m∠HBC

so

m∠EBC=2(m∠EBH)

substitute the given values and solve for a

31a-2=2(4a+45)\\31a-2=8a+90\\31a-8a=92\\23a=92\\a=4

<em>Find the measure of angle EBH</em>

m∠EBH=(4(4)+45)=61°

Remember that

m∠EBH=m∠HBC

therefore

The measure of angle HBC is m∠HBC=61°

8 0
2 years ago
The lifespans of lions in a particular zoo are normally distributed. The average lion lives 12.512.512, point, 5 years; the stan
zaharov [31]

This question was not written properly

Complete Question

The lifespans of lions in a particular zoo are normally distributed. The average lion lives 12.5 years; the standard deviation is 2.4 years. Use the empirical rule (68-95-99.7\%)(68−95−99.7%) to estimate the probability of a lion living between 5.3 to 10. 1 years.

Answer:

Thehe probability of a lion living between 5.3 to 10. 1 years is 0.1585

Step-by-step explanation:

The empirical rule formula states that:

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

3) 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

Mean is given in the question as: 12.5

Standard deviation : 2.4 years

We start by applying the first rule

1) 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.

μ - σ

12.5 -2.4

= 10.1

We apply the second rule

2) 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.

μ – 2σ

12.5 - 2 × 2.4

12.5 - 4.8

= 7.7

We apply the third rule

3)99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.

μ - 3σ

= 12.5 - 3(2.4)

= 12.5 - 7.2

= 5.3

From the above calculation , we can see that

5.3 years corresponds to one side of 99.7%

Hence,

100 - 99.7%/2 = 0.3%/2

= 0.15%

And 10.1 years corresponds to one side of 68%

Hence

100 - 68%/2 = 32%/2 = 16%

So,the percentage of a lion living between 5.3 to 10. 1 years is calculated as 16% - 0.15%

= 15.85%

Therefore, the probability of a lion living between 5.3 to 10. 1 years

is converted to decimal =

= 15.85/ 100

= 0.1585

8 0
2 years ago
A small school with 60 total students records how many of their students attend on each of the 180 days in a school year. the ma
horrorfan [7]

Answer:

For the sampling distribution,

a) Mean = μₓ = 55.0 students.

b) Standard Deviation = 1.8 students.

Step-by-step explanation:

The complete Question is attached to this solution.

The Central limit theorem explains that for the sampling distribution, the mean is approximately equal to the population mean and the standard deviation of the sampling distribution is related to the population standard deviation through

σₓ = (σ/√n)

where σ = population standard deviation = 4

n = sample size = 5

Mean = population mean

μₓ = μ = 55 students.

Standard deviation

σₓ = (σ/√n) = (4/√5) = 1.789 students = 1.8 students to 1 d.p

Hope this Helps!!!

5 0
2 years ago
Theo recorded the means and mean absolute deviations of his language arts and Biology scores. He found the difference in the mea
Rina8888 [55]

The answer is actually A.2 because I just took the test.

8 0
2 years ago
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Answer:

Give me more information


Step-by-step explanation:


5 0
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