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2 years ago

There must be more than 4 campers in a group during free play and the difference between the number of boys, x, and the

Mathematics

2 answers:

Diano4ka-milaya [45]2 years ago

6 0

Answer:

The answer is B. Just took the test

Step-by-step explanation:

RSB [31]2 years ago

4 0

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

x -----> the number of boys

y -----> the number of girls

$x-y \leq 5$

$y \geq x-5$ ----->inequality A

The solution of the inequality A is the shaded area above the solid line $y=x-5$

The slope of the solid line is positive

The y-intercept of the solid line is (0,-5)

The x-intercept of the solid line is (5,0)

$x+y >4$ -----> equation B

The solution of the inequality B is the shaded area above the dashed line $y=-x+4$

The slope of the dashed line is negative

The y-intercept of the solid line is (0,4)

The x-intercept of the solid line is (4,0)

using a graphing tool

the solution of the system of inequalities is the shaded area between the solid line and the dashed line

see the attached figure

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two taps drip together at exactly 1:00pm. one tap then drips again every 68 sec while the other tap continues to drip every 72 s

N76 [4]

The least common multiple of 68 and 72 is 1224 so that means we have to add 1224 minutes to 1:00 pm. Convert that to 24 hour time: 1300. 1224 ÷ 60 is 20.4. so the answer will be 1:20 pm.
P.S. delete this answer if it is wrong and tell me the right answer

5 0

2 years ago

A cooling tower for a nuclear reactor is to be constructed in the shape of a hyperboloid of one sheet. The diameter at the base

timurjin [86]

Answer:

Step-by-step explanation:

Equation for a hyperboloid of one sheet, with center at the origen and axis along z-axis is:

(x/a)² + (y/b)² - (z/c)² = 1 (1)

We have to find a , b, and c

We can express equation (1)

(x/a)² + (y/b)² = (z/c)² + 1 (2)

Now if we cut the hyperboloid with planes parallel to xy plane we get for z = k ( K = 1 , 2 , 3 and so on ) circles of different radius

(x/a)² + (y/b)² = (k/c)² + 1

at z = k = 0 at the base of the hyperboloid d = 300 or r = 150 m

we have

(x/a)² + (y/b)² = 1

x² + y² = a² a² = (150)² a = b = 150

and x² + y² = (150)²

Now the other condition is at 200 m above the base d = 500 m r = 250 m minimum diameter then in equation (2) we have:

(x/a)² + (y/b)² = (z/c)² + 1

(1/a)² [ x² + y² ] = (z/c)² + 1

but x² + y² = r² and in this case r = 250 m then

(250)²/(150)² = (z/c)² + 1 ⇒ (62500/ 22500) = (200/c)² + 1

2,78 = 40000/c² + 1

2.78c² = 40000 + c²

1.78c² = 40000

c² = 40000/1.78

c² = 22471.91

c = 149,91

Then we finally have the equation:

x²/(150)² + y² /(150)² - z²/149,91 = 1

7 0

2 years ago

Make x the subject of the following relations. 2y+3=5x-18

nekit [7.7K]

Step-by-step explanation:

2y+3=5x-18

swap both sides

5x-18=2y+3

add 18 to both sides

5x-18+18=2y+3+18

5x=2y+21

divide both sides by

5x/5=2y+21/5

X=2y+21/5

6 0

2 years ago

What is the volume of a 90' x 20' x 12' house?

mafiozo [28]

21,600 v^3 been a while so not sure wether you need the sq symbol afterword let me know

5 0

2 years ago

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According to the Rational Root Theorem, which function has the same set of potential rational roots as the function g(x) = 3x5 –

SVETLANKA909090 [29]

We have to identify the function which has the same set of potential rational roots as the function $g(x)= 3x^5-2x^4+9x^3-x^2+12$ .

Firstly, we will find the rational roots of the given function.

Let 'p' be the factors of 12

So, p= $\pm 1, \pm 2, \pm 3, \pm 4, \pm 6$

Let 'q' be the factors of 3

So, q= $\pm 1, \pm 3$

So, the rational roots are given by $\frac{p}{q}$ which are as:

$\pm 1, \pm 2, \pm 3, \pm 4, \pm 6, \pm \frac{1}{3}, \pm \frac{2}{3}, \pm \frac{4}{3}$ .

Consider the first function given in part A.

f(x) = $3x^5-2x^4-9x^3+x^2-12$

Here also, Let 'p' be the factors of 12

So, p= $\pm 1, \pm 2, \pm 3, \pm 4, \pm 6$

Let 'q' be the factors of 3

So, q= $\pm 1, \pm 3$

So, the rational roots are given by $\frac{p}{q}$ which are as:

$\pm 1, \pm 2, \pm 3, \pm 4, \pm 6, \pm \frac{1}{3}, \pm \frac{2}{3}, \pm \frac{4}{3}$ .

Therefore, this equation has same rational roots of the given function.

Option A is the correct answer.

4 0

2 years ago

Read 2 more answers