Ari rents the bike for 4 hours, and Meg rents the scooter for 3 hours. What is the total cost of the rentals?

5/8 of the staff are male 5/12 of the staff works part time at the aquarium what is the fraction of the staff being female

Goryan [66]

I believe the answer is 3/8. The whole portion of employees, which is translated as 8/8 is deducted by 5/8, which is the population of male employees.

7 0

2 years ago

Read 2 more answers

Mr Davis is creating a spice mixture for a recipe.2/5 of the spice mixture was oregano 1/3 of the spice mixture was basil the re

attashe74 [19]

Answer: $\frac{11}{15}$

Step-by-step explanation:

You know that:

- 2/5 of the spice mixture was oregano.

- 1/3 of the spice mixture was basil.

Then, to find the fraction of the total amount of spice mixture that was oregano and basil, you must add both fractions, as following:

- Find the least common multiply of the denominators:

$LCM=5*3=15$

- Divide the LCM by each original denominator and multiply the result by each numerator.

- Make the addition.

Then, the result is:

$\frac{(2*3)+(1*5)}{15}=\frac{6+5}{15}=\frac{11}{15}$

7 0

2 years ago

Maggie has exactly $20 to buy decorations for the dance. Streamers cost $2 per roll and balloons are $1.50 per package. Which se

IgorC [24]

Answer:

streamers are closest to her budget.

Step-by-step explanation:

because if you want to buy balloons then you would have to buy 13.3 3 is infinite, but if you bought streamers then you would only buy 10.

6 0

2 years ago

3. Dr. Silas studies the culture of bacteria under a microscope. The function b1(t) = 1200 (1.8)^t represents the number of bact

Dominik [7]

Answer:

(a) the initial count of bacteria

(b) the growth factor (per hour)

(c) the initial count in the second study

(d) the difference in initial counts between the two studies

Step-by-step explanation:

(a) 1200 is b1(0), the initial count of bacteria.

__

(b) 1.8 is the growth factor per hour, the factor that multiplies the previous hour's count to get this hour's count.

__

(c) Assuming b2(t) = 1000(1.8)^t, the value 1000 is the initial count of bacteria in the second study, b2(0).

__

(d) The difference between 1200 and 1000 means the first study started with 200 more bacteria than the second study did

3 0

2 years ago

A tank contains 500 gallons of salt-free water. A brine containing 0.25 lb of salt per gallon runs into the tank at the rate of

Neporo4naja [7]

Answer:

0.0198 lbs per gallon

Step-by-step explanation:

amount of salt free water = 500 gallons

salt rate in = 1 gal/min

salt rate out = 1 gal/min

amount o salt in brine = 0.25 lb per gallon

Let the amount of salt in the tank be A(t) at any time t.

$\frac{dA(t)}{dt} =salt rate in - salt rate out$

salt rate in = 0.25 x 1 = 0.25

salt rate out = $\frac{A(t)\times 1}{500}$

The differential equation is given by

$\frac{dA(t)}{dt} =1 - \frac{A(t)\times 1}{500}$

where, A(0) = 0

So, the equation becomes

$\frac{dA(t)}{dt} + \frac{A(t)}{500} = 1$

Here the integrating factor is $e^{\frac{dt}{500}}=e^{\frac{t}{500}}$

The solution of the above differential equation is given by

$A(t)\times e^{\frac{t}{500}} = \int e^{\frac{t}{500}}dt$

$A(t)\times e^{\frac{t}{500}} = 500\times e^{\frac{t}{500}}+C$

where, C is the integrating constant.

$A(t)=500+Ce^{-\frac{t}{500}}$

Put, A(0) = 0

C = - 500

$A(t)=500\left ( 1-e^{-\frac{t}{500} \right )$

As concentration is defined as

Concentration = Quantity / Volume

$C(t)=\frac{A(t)}{500}$

$C(t)=1-e^{\frac{-t}{500}}$

Now concentration at t = 10 min

Put, t = 10 min

$C(10)=1-e^{\frac{-10}{500}}$

C (10) = 0.0198 lbs per gallon

Thus, teh concentration after 10 min is 0.0198 lbs per gallon.

7 0

2 years ago