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1 year ago

True or false a corollary is a statement that can be easily proved using a theorem

Mathematics

1 answer:

sammy [17]1 year ago

7 0

Answer:

The given statement is true.

Step-by-step explanation:

A corollary is a statement that can be easily proved using a theorem. This statement is true.

A corollary is usually defined as some idea formed from something that is already existing or already been proven.

This is the reason it is not difficult to prove as it has already been proven.

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Researchers have a sample size of 24 , and they are using the Student's t-distribution. What are the degrees of freedom and how

DerKrebs [107]

Answer:

For this case assuming that the random variable is X

$df = n-1$

And replacing n = 24 we got:

$df = 24-1=23$

And we notate the distribution we got: $X \sim t_{n-1}= t_{23}$

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

For this case assuming that the random variable is X

$df = n-1$

And replacing n = 24 we got:

$df = 24-1=23$

And we notate the distribution we got: $X \sim t_{n-1}= t_{23}$

7 0

1 year ago

The following table shows the number of hours a cleaning company spends cleaning apartments.

mart [117]

First, plot the points in a graph to see the general trend. The independent variable is time. I used MS Excel to plot the points in a graph, as shown in the attached picture.

1. The relationship is linear as shown in the general trend.
2. The relationship presents that as time increases, the number of apartments cleaned also increases. The two variables are directly proportional.
3. The rate of change represents the slope of the line. Choose any two points and find the slope.

m = (6-3)/(2-1) = 3 apartments cleaned/hour

7 0

2 years ago

In Juneau, Alaska, the 30-year annual snowfall average is 86.7 inches with a standard deviation of 40.4 inches. The last four ye

marusya05 [52]

The expected value of the amount of average snowfall for over 30 years is 86.7 inches with a standard deviation of 40.4 inches. To verify if this particular trend continues, we must check the significance value of the amount snowfall for the past four years. Given that the snowfall for past years are as follows: 115.7 inches, 62.9 inches, 168.5 inches, and 135.7 inches. Thus the mean of the sample would be: (115.7 + 62.9 + 168.5 + 135.7)/4 = 120.7 inches. To compute for the z-score, we have z-score = (x – μ) / (σ / √n) where x is the computed/measured value, μ is the expected mean, σ is the standard deviation, and n is the number of samples. Using the information we have, z-score (z) = (120.7 - 86.7) / (40.4/ √4) = 1.68 In order to reject the null hyptohesis our probability value must be less than the significance level of 5%. For our case, since z = 1.68, P-value = 0.093 > 0.05. Therefore, the answer is B.

5 0

2 years ago

Read 2 more answers

The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding

Andru [333]

Answer:

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Step-by-step explanation:

Values (x) ∑(Xi-X)^2

----------------------------------

29.1 0.1702

28.5 1.0252

28.8 0.5077

29.4 0.0127

29.8 0.0827

30.1 0.3452

30.6 1.1827

----------------------------------------

236.1 3.4088

Mean = 236.1 / 8 = 29.51

$S_{x}=\sqrt{3.4088/(8-1)}=0.6978$

Statement of the null hypothesis:

H0: u ≥ 30 the mean wedding cost is not less than $30,000

H1: u < 30 the mean wedding cost is less than $30,000

Test Statistic:

$t=\frac{X-u}{S/\sqrt{n}}=\frac{29.51-30}{0.6978/\sqrt{8}}= \frac{-0.49}{0.2467}=-1.9861$

Test criteria:

SIgnificance level = 0.05

Degrees of freedom = df = n - 1 = 8 - 1 = 7

Reject null hypothesis (H0) if

$t$

Finding in the t distribution table α=0.05 with df=7, we have

$t_{0.05,7}=2.365$

$t>-t_{0.05,7}$ = -1.9861 > -2.365

Result: Fail to reject null hypothesis

Conclusion: Do no reject the null hypothesis

u ≥ 30 the mean wedding cost is not less than $30,000

There is no sufficient evidence to support the claim that wedding cost is less than $30000.

Hope this helps!

5 0

2 years ago

Two pools are being drained. To start, the first pool had 3700 liters of water and the second pool had 4228 liters of water. Wat

cestrela7 [59]

Answer:

Pool 1 will be drained out just over a minute before pool 2.

Step-by-step explanation:

Pool 1

3700/31 = 119.35minutes

Pool 2

4228/42 = 100.67minutes

Pool 1 will be drained out just over a minute before pool 2

3 0

2 years ago