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Lady bird [3.3K]
2 years ago
12

In 1998 the average income for middle class families in the US was $37,100 with a population standard deviation of $6362. We wan

ted to check how representative the 1998 GSS survey was of the American adult population from which it was drawn. The 1998 GSS survey found a mean income of $36,670 for its sample of 1225 middle-class American adults. Use this information to answer the following questions:______.
Which test statistic would be appropriate for this research problem?
A. Z test
B. T test
C. Chi square
D. None of the above
Mathematics
1 answer:
sammy [17]2 years ago
5 0

Answer:

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

The best answer would be:

A. Z test

Step-by-step explanation:

Data given and notation  

\bar X=36670 represent the mean average

\sigma=6362 represent the population standard deviation for the sample  

n=1225 sample size  

\mu_o =37100 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal or not to 37100, the system of hypothesis would be:  

Null hypothesis:\mu =37100  

Alternative hypothesis:\mu \neq 37100  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

The best answer would be:

A. Z test

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a rectangular field has side lengths that measure 9/10 mile and 1/2 mile. What is the area of the field
GrogVix [38]

Answer:

9/20, or 0.45 mile.

Step-by-step explanation:\\

To find the area of a rectangle, multiply length times width. In this problem we are given both the length and width.

\frac{9}{10} × \frac{1\\}{2} is just 9/20, which is 0.45.

7 0
2 years ago
Dominic earns $285 per week plus an 8% commission rate on all his sales. If Dominic sells $4,213 worth of merchandise in one wee
nexus9112 [7]
(4213*.08)+285=
337.04+285=
622.04
3 0
2 years ago
What is the equation of a line that is parallel to the line 2x + 5y = 10 and passes through the point (–5, 1)? Check all that ap
Bond [772]

So the right options are:

y=-\frac{2}{5}x-1

2x+5y = -5

y-1=-\frac{2}{5}(x+5)

Further explanation:

Given equation of line is:

2x+5y=10

We have to convert it into point-slope form

2x+5y=10\\5y=-2x+10\\Dividing\ both\ sides\ by\ 5\\y=-\frac{2}{5}x+\frac{10}{5}\\y=-\frac{2}{5}x+2

The co-efficient of x is the slope of the line

So,

m= -\frac{2}{5}

As the required line is parallel to given line, it will also have same slope.

Let m1 be the slope of required line

Then the line will be:

y=m_1x+b

Putting the value of slope

y=\frac{2}{5}x+b

Putting (-5,1) in the equation to find the value of b

1=-\frac{2}{5}(-5)+b\\1=2+b\\b=1-2\\b=-1

Putting the values of slope and b in equation

y=-\frac{2}{5}x-1

Multiplying the whole equation by 5 will give us:

5y = -2x-5

2x+5y = -5

Another form of equation of line is Point-slope form

y-y_1=m(x-x_1)

Putting the values of slope and point in the equation, we get

y-1=-\frac{2}{5}(x+5)

So the right options are:

y=-\frac{2}{5}x-1

2x+5y = -5

y-1=-\frac{2}{5}(x+5)

Keywords: Point-Slope form, Parallel lines

Learn more about point slope form at:

  • brainly.com/question/4464845
  • brainly.com/question/4522984

#LearnwithBrainly

4 0
2 years ago
Read 2 more answers
Functions f(x) and g(x) are shown: f(x) = x2 g(x) = x2 − 8x + 16 In which direction and by how many units should f(x) be shifted
denis23 [38]

Answer:

Shift right by 4

Step-by-step explanation:

Given f(x)=x^2

g(x)= x^2-8x+16

Using

Horizontal Shift theorem dealing with the question

If the graph were to be move to to the right, we must use of graph f (x-L)

Where L= 4 and

NOTE:

POSITIVE L MAKES GRAPH SHIFT RIGHT

2) NEGATIVE MAKES GRAPH SHIFT LEFT

g(x)= x^2-8x+16

If we factorize this we have

(x-4)(x-4)

Since the two terms are the same we have (x-4)^2

Then it can move by factor of 4 to the right since constant 4 can be substracted from the parents function

4 0
2 years ago
For what values of m does the graph of y = 3x^2 + 7x + m have two x-intercepts? a) m>12/49 b) m<12/49 c) m<49/12 d) m&g
den301095 [7]

The quadratic formula, has a part we call the "discriminant" defined by the variables that are inside the square root, and is denotated by "delta":

<span>Δ=<span>b2</span>−4ac</span> Whenever we solve a quadratic equation that is complete and we analyze the discriminant, we can get 3 scenarios: <span>if→Δ>0<span>=></span>∃<span>x1</span>,<span>x2</span>/a<span>x2</span>+bx+c=0</span> This just means: "if the discriminant is greater than zero, there will exist two x-intercepts" And for the second scenario: <span>if→Δ=0→∃<span>xo</span>/a<span>x2</span>+bx+c=0</span> This means: "if the discriminant is equal to zero, there will be one and only one x-intercept" And for the last scenario: <span>if→Δ<0→∃x∉R/a<span>x2</span>+bx+c=0</span> This means that :"if the discriminant is less than zero, there will be no x-intercepts" So, if we take your excercise and analyze the the discriminant: <span>3<span>x2</span>+7x+m=y</span> we will find the values that satisfy y=0 : <span>3<span>x2</span>+7x+m=0</span> And we'll analyze the discriminant: <span>Δ=<span>72</span>−4(3)(m)</span> And we are only interested in the values that make the discriminant equal zero: <span><span>72</span>−4(3)(m)=0</span> All you have to do is solve for "m".

6 0
2 years ago
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