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mihalych1998 [28]
2 years ago
12

If number A is a 2-digit number and its digits are transposed to form number B, then the difference between the larger of the tw

o numbers and the smaller of the two numbers must be divisible by _____.
A.8
B.7
C.9
D.an even number
Mathematics
2 answers:
galben [10]2 years ago
8 0
If the original number is ab it has a value of

10a+b  when it is reversed it will have a value of 10b-a

10b+a-10a-b  is the differences which is equal to

9b-9a

So the numbers must be divisible by 9
Ganezh [65]2 years ago
7 0

Answer:

9 is the correct answer

Step-by-step explanation:

Apex

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Answer: he will be able to play 32.6 games at the arcade

Step-by-step explanation:

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Mr Russo exchanged 200 euros for 270 dollars.how man dollars would he get for 300 euros
Nostrana [21]

200 euros       300 euros

--------------- = -----------------------------

270 dollars      x dollars

using cross products

200 * x = 270 * 300

divide each side by 200

x = 270 * 300/200

x =405 dollars

6 0
2 years ago
Which is true about the completely simplified difference of the polynomials a3b + 9a2b2 − 4ab5 and a3b − 3a2b2 + ab5? The differ
tamaranim1 [39]
<span>Let be A =a3b +9a2b2-4ab5, and B=a3b-3a2b2+ab5,so the difference can be defined as A - B =a3b +9a2b2-4ab5 -(a3b-3a2b2+ab5), when there is negative sign in front of the parathesis, all the inside signs must change: that is as follow: A- B= a3b +9a2b2-4ab5 - a3b + 3a2b2 - ab5= a3b-a3b +9a2b2+3a2b2-4ab5- ab5= 12a2b2 -5ab5, the fist term has 2+2=4, as a degree,the second term has 1 +5 =6, so the true answer : The difference is a binomial with a degree of 6</span>
6 0
2 years ago
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There are exactly π radians in a semicircle. There are exactly π radians in a full circle. There are approximately radians in a
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pi radians in a semicircle (half circle)

2pi radians in a full circle.

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2pi radians is equivalent to 360 degrees.


8 0
2 years ago
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Assume that a fair die is rolled. The sample space is , 1, 2, 3, 4, 56, and all the outcomes are equally likely. Find P8. Expres
liraira [26]

Answer:

P\left(8\right)=0

Step-by-step explanation:

Assuming that a fair die is rolled.

  • The sample space is 1, 2, 3, 4, 5, 6 and all the outcomes are equally likely.

Let  X  be the set of all possible outcomes. Let  A  be an outcome.

So, the probability that  A  occurs is:

                                                        P\left(A\right)=\frac{|A|}{|X|}

As the set of all possible outcomes of the roll of a single die is:

X=\left\{1,2,3,4,5,6\right\}

Observe that

|X|=6

Here  

|A|=0   because 8 is not in the set sample space. So, the outcome of occurring the number 8 is not possible from the all possible outcomes.

So, the probability must be zero.

In other words,

                        P\left(A\right)=\frac{|A|}{|X|}

                         P\left(8\right)=\frac{0}{6}=0

Therefore,

                   P\left(8\right)=0

5 0
2 years ago
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