Answer:
Find out the what was the dealership's profit on these two vehicles .
To prove
As given
A dealership purchased a four-door sedan for $17,000 and then sold it at 15% markup.
15 % is written in the decimal form.
= 0.15
Mark up price for sedan = 0.15 × 17000
= $ 2550
As given
The dealership paid the buyer $4000 for a trade-in, which was sold the following week at 25% markup.
25 % is written in the decimal form .
= 0.25
Mark up price for trade-in = 0.25 × 4000
= $1000
Than
The dealership's profit on two vehicles = Mark up price for sedan + Mark up price for trade-in
= $2550 + $1000
= $3550
Therefore the dealership's profit on these two vehicles iss $3550 .
<u>Given</u>:
Given that the regular decagon has sides that are 8 cm long.
We need to determine the area of the regular decagon.
<u>Area of the regular decagon:</u>
The area of the regular decagon can be determined using the formula,
where s is the length of the side and n is the number of sides.
Substituting s = 8 and n = 10, we get;
Simplifying, we get;
Rounding off to the nearest whole number, we get;
Thus, the area of the regular decagon is 642 cm²
Hence, Option B is the correct answer.
Answer:
1)
Using the condition given:
So then if we want to create an equation we need to do this:
With K a constant. For this case the period of a pendulumn is given by this general expression:
Where L is the length in m and g the gravity .
2)
If we square both sides of the equation we got:
And solving for L we got:
Replacing we got:
3)
Step-by-step explanation:
Part 1
For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.
Using the condition given:
So then if we want to create an equation we need to do this:
With K a constant. For this case the period of a pendulumn is given by this general expression:
Where L is the length in m and g the gravity .
Part 2
For this case using the function in part a we got:
If we square both sides of the equation we got:
And solving for L we got:
Replacing we got:
Part 3
For this case using the function in part a we got:
Replacing we got: