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DaniilM [7]
1 year ago
6

A regular decagon has sides that are 8 cm long. What is the area of the figure? Round to the nearest whole number.

Mathematics
1 answer:
blsea [12.9K]1 year ago
5 0

<u>Given</u>:

Given that the regular decagon has sides that are 8 cm long.

We need to determine the area of the regular decagon.

<u>Area of the regular decagon:</u>

The area of the regular decagon can be determined using the formula,

A=\frac{s^{2} n}{4 \tan \left(\frac{180}{n}\right)}

where s is the length of the side and n is the number of sides.

Substituting s = 8 and n = 10, we get;

A=\frac{8^{2} \times 10}{4 \tan \left(\frac{180}{10}\right)}

Simplifying, we get;

A=\frac{64 \times 10}{4 (\tan \ 18)}

A=\frac{640}{4 (0.325)}

A=\frac{640}{1.3}

A=642.3

Rounding off to the nearest whole number, we get;

A=642 \ cm^2

Thus, the area of the regular decagon is 642 cm²

Hence, Option B is the correct answer.

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The graph of the function f(x) = (x + 2)(x + 6) is shown below.
iren [92.7K]

Answer:

Step-by-step explanation:

f(x) = (x + 2)(x +6)

1) The function is positive for all real values of x where   x > –4 :

COUNTER-EXAMPLE : x =  - 3   you have -3>-4 but   (-3+2)(-3+6) = -1 ×3 =-3 no positive .

2) The function is positive for all real values of x where

x < –6 or x > –3.

COUNTER-EXAMPLE : x =  - 2.5   you have -2.5>-3 but   (-2.5+2)(-2.5+6) = -0.5 ×3.5 =-1.75 no positive .

same method for the statement : "The function is negative for all real values of x where

x < –2."

conclusion : statement about the function is true: "The function is negative for all real values of x where

–6 < x < –2."

.

4 0
2 years ago
Read 2 more answers
You have a small marble statue of Mozart that is 10 inches tall and is made of 16 cu. inches of marble. The original statue in V
vagabundo [1.1K]

Answer:

0.08 cubic feet.

Step-by-step explanation:

You have a small marble statue of Mozart that is 10 inches tall and is made of 16 cu. inches of marble.

The original statue in Vienna is 7 feet tall.

First we will convert this to inches as one relation is given in inches.

1 feet = 12 inches

7 feet = 12\times7=84 inches

Let the amount of marble used for 84 inches statue be = x

We can relate both the conditions in the following way:

\frac{10}{16} =\frac{84}{x}

10x=16\times84

10x=1344

x = 134.40 cubic inches

Now, 1 cubic inch = \frac{1}{1728} cubic foot

So, 134.40 cubic inches = \frac{134.40}{1728} cubic foot

= 0.0777 cubic feet rounding to 0.08 cubic feet.

6 0
2 years ago
Four friends are playing a game. They randomly choose a handful of marbles from a bag. The player with the highest ratio of blue
Monica [59]

We are given the number of Blue and Purple Marbles for each of the four friends. So first we have to find the ratio of blue marbles to purple marbles for each of them.

A) Rosa

Number of blue marbles = 10

Number of purple marbles = 12

Ratio of blue to purple marbles = \frac{10}{12}=0.833

B) Chi

Number of blue marbles = 5

Number of purple marbles = 6

Ratio of blue to purple marbles = \frac{5}{6}=0.833

C) Alberto

Number of blue marbles = 5

Number of purple marbles = 12

Ratio of blue to purple marbles = \frac{5}{12}=0.417

D) Pedro

Number of blue marbles = 10

Number of purple marbles = 6

Ratio of blue to purple marbles = \frac{10}{6}=1.667

From the above calculations we can see that Pedro has the highest value of ratio for blue marbles to purple marbles. Also we can see Pedro is the only one for whom the number of blue marbles is more than the number of purple marbles. So this confirms that our calculation is correct.

Thus, the player which gets to go first is Pedro.

4 0
1 year ago
Read 2 more answers
Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4
german

Answer:

range is  between 55.5 to 64.5

Step-by-step explanation:

Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4.5 inches

68% is 1 standard deviation from mean

To get the range of 1 standard deviation we add and subtract standard deviation from mean

mean = 60

standard deviation = 4.5

60 - 4.5= 55.5

60+4.5 = 64.5

1 standard deviation is between 55.5 to 64.5

That is 68% range is  between 55.5 to 64.5

8 0
2 years ago
g An irate student complained that the cost of textbooks was too high. He randomly surveyed 36 other students and found that the
blagie [28]

Answer:

A 90% confidence interval of the true mean is [$119.86, $123.34].

Step-by-step explanation:

We are given that an irate student complained that the cost of textbooks was too high. He randomly surveyed 36 other students and found that the mean amount of money spent on textbooks was $121.60.

Also, the standard deviation of the population was $6.36.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                              P.Q.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean amount of money spent on textbooks = $121.60

            \sigma = population standard deviation = $6.36

            n = sample of students = 36

            \mu = population mean

<em>Here for constructing a 90% confidence interval we have used One-sample z-test statistics as we know about population standard deviation.</em>

<em />

So, 95% confidence interval for the population mean, \mu is ;

P(-1.645 < N(0,1) < 1.645) = 0.90  {As the critical value of z at 5% level

                                                      of significance are -1.645 & 1.645}  

P(-1.645 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.645) = 0.90

P( -1.645 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

P( \bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.90

<u>90% confidence interval for</u> \mu = [ \bar X-1.645 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.645 \times {\frac{\sigma}{\sqrt{n} } } ]

                                      = [ 121.60-1.645 \times {\frac{6.36}{\sqrt{36} } } , 121.60+1.645 \times {\frac{6.36}{\sqrt{36} } } ]

                                      = [$119.86, $123.34]

Therefore, a 90% confidence interval of the true mean is [$119.86, $123.34].

5 0
2 years ago
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