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dolphi86 [110]
2 years ago
15

Schadek Silkscreen Printing Inc. purchases plastic cups and imprints them with logos for sporting events, proms, birthdays, and

other special occasions. Zack Schadek, the owner, received a large shipment this morning. To ensure the quality of the shipment, he selected a random sample of 300 cups and inspected them for defects. He found 15 to be defective.
a. What is the estimatedproportion defective in the population?

b. Develop a 95 percent confidenceinterval for the proportion defective.

c. Zack has an agreement withhis supplier that he is to return lots that are 10 percent or moredefective.
Mathematics
1 answer:
Ivahew [28]2 years ago
5 0

Answer:

(a) The estimated proportion of defective in the population is 0.05.

(b) The 95% confidence interval for the proportion defective cups is (2.5%, 7.5%).

(c) Zack does not needs to return the lots.

Step-by-step explanation:

Let <em>X</em> = number of defective cups.

The random sample of cups selected is of size, <em>n</em> = 300.

The number of defective cps in the sample is, <em>X</em> = 15.

(a)

The proportion of the defective cups in the population can be estimated by the sample proportion because the sample selected is quite large.

The sample proportion of defective cups is:

\hat p=\frac{X}{n}=\frac{15}{300}=0.05

Thus, the estimated proportion of defective in the population is 0.05.

(b)

The (1 - <em>α</em>)% confidence interval for population proportion is:

CI=\hat p \pm z_{\alpha/2}\times\sqrt{\frac{\hat p(1-\hat p)}{n}}

Compute the critical value of <em>z</em> for 95% confidence level as follows:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the 95% confidence interval for <em>p</em> as follows:

CI=\hat p \pm z_{\alpha/2}\times\sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.05 \pm 1.96\times\sqrt{\frac{0.05(1-0.05)}{300}}

     =0.05\pm 0.025\\=(0.025, 0.075)\\

Thus, the 95% confidence interval for the proportion defective cups is (2.5%, 7.5%).

(c)

It is provided that Zack has an agreement with his supplier that he is to return lots that are 10% or more defective.

The 95% confidence interval for the proportion defective is (2.5%, 7.5%). This implies that 95% of the lots have 2.5% to 7.5% defective items.

Thus, Zack does not needs to return the lots.

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